

Trần Châu Anh
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a) P = \(\dfrac{2}{3}\)-(-\(\dfrac{1}{4}\))+\(\dfrac{3}{5}\)-\(\dfrac{7}{45}\)-(\(\dfrac{-5}{9}\))+\(\dfrac{1}{12}\)+\(\dfrac{1}{35}\)
P = \(\dfrac{2}{3}\)+\(\dfrac{1}{4}\)+\(\dfrac{3}{5}\)-\(\dfrac{7}{45}\)+\(\dfrac{5}{9}\)+\(\dfrac{1}{12}\)+\(\dfrac{1}{35}\)
P = (\(\dfrac{2}{3}\)+\(\dfrac{1}{4}\)+\(\dfrac{1}{12}\))+(\(\dfrac{3}{5}\)+\(\dfrac{5}{9}\)-\(\dfrac{7}{45}\))+\(\dfrac{1}{35}\)
P = (\(\dfrac{8}{12}\)+\(\dfrac{3}{12}\)+\(\dfrac{1}{12}\))+(\(\dfrac{27}{45}\)+\(\dfrac{25}{45}\)-\(\dfrac{7}{45}\))+\(\dfrac{1}{35}\)
P = 1+1+\(\dfrac{1}{35}\)
P = 2+\(\dfrac{1}{35}\)
P = \(\dfrac{71}{35}\)
a) A = (\(\dfrac{1}{3}\)-\(\dfrac{8}{15}\)-\(\dfrac{1}{7}\))+(\(\dfrac{2}{3}\)+\(\dfrac{-7}{15}\)+1\(\dfrac{1}{7}\))
A = \(\dfrac{1}{3}\)-\(\dfrac{8}{15}\)-\(\dfrac{1}{7}\)+\(\dfrac{2}{3}\)+\(\dfrac{-7}{15}\)+\(\dfrac{8}{7}\)
A = (\(\dfrac{1}{3}\)+\(\dfrac{2}{3}\))+(\(\dfrac{-8}{15}\)+\(\dfrac{-7}{15}\))+(\(\dfrac{-1}{7}\)+\(\dfrac{8}{7}\))
A = 1+(-1)+1
A = 1