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Ngọc Diệp Nguyễn
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2025-02-17 17:42:40
Từ: �2(�+�)=�2(�+�)⇔�2�−��2+��2−��2=0⇔��(�−�)+�(�−�)(�+�)=0.a2(b+c)=b2(a+c)⇔a2b−ab2+ca2−cb2=0⇔ab(a−b)+c(a−b)(a+b)=0.
⇔(�−�)(��+��+��)=0⇔(a−b)(ab+bc+ac)=0. Do �≠�⇒��+��+��=0a=b⇒ab+bc+ac=0(1)
Mặt khác, xét hiệu:
�2(�+�)−�2(�+�)=��2−�2�+��2−�2�=��(�−�)+�(�−�)(�+�)=c2(a+b)−a2(b+c)=ac2−a2c+bc2−a2b=ac(c−a)+b(c−a)(c+a)=
=(�−�)(��+��+��)=0=(c−a)(ac+bc+ab)=0
Do đó: �=�2(�+�)=�2(�+�)=2013.H=c2(a+b)=a2(b+c)=2013.