Sơn Tinh ở núi Tản Viên.

\(-69+53+46+\left(-94\right)+\left(-14\right)+78\\ =-69+53+46-94-14+78\\ =-69+99-108+78\\ =30-30\\ =0.\)

\(-37+54+\left(-70\right)+\left(-163\right)+246\\ =-37+54-70-163+246\\ =\left(-37-163\right)+\left(54+246\right)-70\\ =-200+300-70\\ =100-70\\ =30.\)

\(a,3^7.27^5.81^3\\ =3^7.\left(3^3\right)^5.\left(3^4\right)^3\\ =3^7.3^{15}.3^{12}\\ =3^{34}\\ b,100^6.1000^5.10000^4\\ =100^6.100^{10}.100^{12}\\ =100^{28}\\ c,125^4:5^8\\ =5^{12}:5^8\\ =5^4.\)

\(A=1+2+3+...+50\)

Tổng của \(A\) là:

    \(\left[\left(50-1\right):1+1\right].\left(50+1\right):2=1275\)

\(B=1+3+5+7+...+49\)

Tổng của \(B\) là:

     \(\left[\left(49-1\right):2+1\right].\left(49+1\right):2=625.\)

\(a=1+3+3^2+..+3^{2006}\\ \Rightarrow3a=3+3^2+3^3+3^4+...+3^{2007}\\ \Rightarrow a-3a=1-3^{2007}\\ \Rightarrow-2a=1-3^{2007}\\ \Rightarrow a=\dfrac{-1-3^{2007}}{2}\)

Thay \(a,b\) vào biểu thức \(b-2a\), ta có:

\(3^{2007}+\dfrac{1-3^{2007}}{2}.2\\ =3^{2007}+1-3^{2007}\\ =\left(3^{2007}-3^{2007}\right)+1\\ =1.\)

\(97.99\\ =97.\left(100-1\right)\\ =9700-97\\ =9603.\)

\(A=\left\{6;12;18;24;30;36;42;48\right\}\)

\(\Rightarrow\) Sorry nãy mk nhìn nhầm ạ.

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