

Hoàng Thanh Tuấn
Giới thiệu về bản thân



































a) A=\(\frac16\)
b) B=\(\frac{\sqrt{x}+1}{\sqrt{x}_{}-1}\)
c) P = A.B = \(\frac{x}{\sqrt{x}-1}\) ta co P\(\le\) 4
nen thay P vao ta co x=4
a) A=\(\frac16\)
b) B=\(\frac{\sqrt{x}+1}{\sqrt{x}_{}-1}\)
c) P = A.B = \(\frac{x}{\sqrt{x}-1}\) ta co P\(\le\) 4
nen thay P vao ta co x=4
a) A=\(\frac16\)
b) B=\(\frac{\sqrt{x}+1}{\sqrt{x}_{}-1}\)
c) P = A.B = \(\frac{x}{\sqrt{x}-1}\) ta co P\(\le\) 4
nen thay P vao ta co x=4
xac suat la 1/3
25%
p=(x+24x+4−x8x):(x−2xx−1−x2)=(x+24x−x−48x):[x⋅(x−2)x−1−x2]=[x+24x−(x−2)(x+2)8x]:[x⋅(x−2)x−1−x2]=[(x−2)(x+2)4x⋅(x−2)−8x]:[x⋅(x−2)x−1−2⋅(x−2)]=[(x−2)(x+2)4x−8x−8x]:[x⋅(x−2)x−1−2x+4]=[(x−2)(x+2)−4x−8x]:[x⋅(x−2)−x+3]
=[−4x⋅(x+2)(x−2)(x+2)]:[−x+3x⋅(x−2)]=−4xx−2⋅x⋅(x−2)−x+3=−4x−x+3=4xx−3=[(x−2)(x+2)−4x⋅(x+2)]:[x⋅(x−2)−x+3]=x−2−4x⋅−x+3x⋅(x−2)=−x+3−4x=x−34x