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Phạm Thị Khánh Linh
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2025-02-14 18:12:20
a) Php=(P^2.R)/U^2=(50000/500)^2.4=40000
Độ giảm thế U=(RP)/U=(4.50000)/500=400V
H=(P-Php)/P=(50000-40000)/50000=20%
U nơi tiêu thụ=500-400=100V
b) U1/U2=0,1=>U2=U1/0,1=500/0,1=5000V
Độ giảm thế U=(RP)/U=(4.50000)/5000=40V
I2=P/U2=50000/5000=10A
Php2=R.I2^2=4.10^2=400W
H=(P-Php2)/P=(50000-400)/50000=99,2%
U=5000-40=4960
2025-02-14 17:55:37
Chiều dòng điện cảm ứng điện từ: B->A->D->C
2025-02-14 17:46:49
a) I=q/t=Ne/t= (10^8.1,6.10^-19)/1=0,16A
b) F=BILsina=5.10^-3.0,5.0,16.sin90=4.10^-4N