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Vũ Đình Mạnh
Giới thiệu về bản thân
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ko
a,chu vi hcn là
(25+18)*2=86
đs 86cm
b, đổi 1 dm = 10 cm
chu vi hcn là
(16+10)*2=52
đs52 cm
7x8x3x5/8x7x49x5=3/49
góc MON=xOM+xON+140o+40o+180o->M,O,N thẳng hàng . MN cắt xx' tạo O->xON,xOm là 2 góc đối đỉnh
a,thể tích hình hộp chữ nhật là:5.4.3=60(cm)
b,thể tích hình lăng trụ đứng tam giác là : 3.4/2 .5 = 30 (cm)
diện tích xung quanh hình lăng trụ là : (3+4+5).5=60(cm)
x+5/6=4/3 x:2^4=8^3 13/4.(5/52-x)=1/4
x=4/3-5/6 x:2^4=(2^3)^3 5/52-x=1/13
x=8/6-5/6 x:2/4=2/9 x=5/52-1/13
x=1/2 x=2/9.2/4 x=1/52
x=2^13
a,5/9-(1/3)^2=5/9-1/9=4/9
b,1/5x-3/2+-17/2x1/5=1/5x(-17/2+-3/2)=1/5x10=-2
c,1+(-2/5 + 11/13 ) - (3/5-2/13)=1+-2/5 +11/13 - 3/5 +2/13= 1+(-2/5+-3/5)+(11/13+2/13)=1+(-1)+1=1