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Đặng Thị Phương Hiền
Giới thiệu về bản thân
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a: \(\dfrac{19}{7}\)+\(\dfrac{5}{6}\)=\(\dfrac{114}{42}\)+\(\dfrac{35}{42}\)=\(\dfrac{149}{42}\)
b:\(\dfrac{17}{6}\)-2=\(\dfrac{17}{6}\)-\(\dfrac{2}{1}\)=\(\dfrac{17}{6}\)-\(\dfrac{12}{6}\)=\(\dfrac{15}{6}\)=\(\dfrac{5}{2}\)
c:9x\(\dfrac{7}{10}\)=\(\dfrac{9}{1}\)x\(\dfrac{7}{10}\)=\(\dfrac{63}{10}\)
d: \(\dfrac{11}{7}\):\(\dfrac{22}{21}\)=\(\dfrac{11}{7}\)x\(\dfrac{21}{22}\)=\(\dfrac{3}{2}\)
a: \(\dfrac{19}{7}\)+\(\dfrac{5}{6}\)=\(\dfrac{114}{42}\)+\(\dfrac{35}{42}\)=\(\dfrac{149}{42}\)
b:\(\dfrac{17}{6}\)-2=\(\dfrac{17}{6}\)-\(\dfrac{2}{1}\)=\(\dfrac{17}{6}\)-\(\dfrac{12}{6}\)=\(\dfrac{15}{6}\)=\(\dfrac{5}{2}\)
c:9x\(\dfrac{7}{10}\)=\(\dfrac{9}{1}\)x\(\dfrac{7}{10}\)=\(\dfrac{63}{10}\)
d: \(\dfrac{11}{7}\):\(\dfrac{22}{21}\)=\(\dfrac{11}{7}\)x\(\dfrac{21}{22}\)=\(\dfrac{3}{2}\)
a: 341km2 < 341000h
b:129000 mm2 > 12dm2 9mm2
c: \(\dfrac{1}{25}\)ha = 400 m2
a: 341km2 < 341000h
b:129000 mm2 > 12dm2 9mm2
c: \(\dfrac{1}{25}\)ha = 400 m2
a: 341km2 < 341000h
b:129000 mm2 > 12dm2 9mm2
c: \(\dfrac{1}{25}\)ha = 400 m2
\(4\dfrac{5}{6}\)
2\(\dfrac{3}{8}\)
\(4\dfrac{5}{6}\)
2\(\dfrac{3}{8}\)
Độ dài một cạnh của mảnh vườn đó là : 100 cm
Nửa chu vi sân chơi hình chữ nhật là: 240: 2=120m
chiều dài sân chơi hình chữ nhật là: 120x\(\dfrac{2}{3}\)= 80 m
chiều rộng sân chơi hình chữ nhật là: 120 - 80 = 40 m
Đáp số : Chiều dài 80m
Chiều rộng 40m
a:178,9; 17,89; 1,789; 1,709
b: 1,709= 1,71