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a) \(\frac{5}{17} - \frac{25}{31} + \frac{12}{17} + \frac{- 6}{31}\)

\(= \left(\right. \frac{5}{17} + \frac{12}{17} \left.\right) + \left(\right. \frac{- 25}{31} + \frac{- 6}{31} \left.\right)\)

\(= \frac{17}{17} + \frac{- 31}{31}\)

\(= 1 + \left(\right. - 1 \left.\right) = 0\)

b) \(\frac{17}{8} : \left(\right. \frac{27}{8} + \frac{11}{4} \left.\right)\)

\(= \frac{17}{8} : \left(\right. \frac{27}{8} + \frac{22}{8} \left.\right)\)

\(= \frac{17}{8} : \frac{49}{8} = \frac{17}{8} \cdot \frac{8}{49} = \frac{17}{49}\)

c) \(\frac{1}{5} \cdot \frac{11}{16} + \frac{1}{5} \cdot \frac{5}{16} + \frac{4}{5}\)

\(= \frac{1}{5} \cdot \left(\right. \frac{11}{16} + \frac{5}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. \frac{16}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. 1 + 4 \left.\right) = \frac{1}{5} \cdot 5 = 1\)

d) \(\frac{5}{6} : 25 - 2 + \frac{- 7}{3} \cdot \frac{2}{7}\)

\(= \frac{5}{6} \cdot \frac{1}{25} - 2 + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{6}{3} + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{8}{3} = \frac{1}{30} - \frac{80}{30} = \frac{- 79}{30}\)\(\)

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a) \(\frac{5}{17} - \frac{25}{31} + \frac{12}{17} + \frac{- 6}{31}\)

\(= \left(\right. \frac{5}{17} + \frac{12}{17} \left.\right) + \left(\right. \frac{- 25}{31} + \frac{- 6}{31} \left.\right)\)

\(= \frac{17}{17} + \frac{- 31}{31}\)

\(= 1 + \left(\right. - 1 \left.\right) = 0\)

b) \(\frac{17}{8} : \left(\right. \frac{27}{8} + \frac{11}{4} \left.\right)\)

\(= \frac{17}{8} : \left(\right. \frac{27}{8} + \frac{22}{8} \left.\right)\)

\(= \frac{17}{8} : \frac{49}{8} = \frac{17}{8} \cdot \frac{8}{49} = \frac{17}{49}\)

c) \(\frac{1}{5} \cdot \frac{11}{16} + \frac{1}{5} \cdot \frac{5}{16} + \frac{4}{5}\)

\(= \frac{1}{5} \cdot \left(\right. \frac{11}{16} + \frac{5}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. \frac{16}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. 1 + 4 \left.\right) = \frac{1}{5} \cdot 5 = 1\)

d) \(\frac{5}{6} : 25 - 2 + \frac{- 7}{3} \cdot \frac{2}{7}\)

\(= \frac{5}{6} \cdot \frac{1}{25} - 2 + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{6}{3} + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{8}{3} = \frac{1}{30} - \frac{80}{30} = \frac{- 79}{30}\)\(\)

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a) \(\frac{5}{17} - \frac{25}{31} + \frac{12}{17} + \frac{- 6}{31}\)

\(= \left(\right. \frac{5}{17} + \frac{12}{17} \left.\right) + \left(\right. \frac{- 25}{31} + \frac{- 6}{31} \left.\right)\)

\(= \frac{17}{17} + \frac{- 31}{31}\)

\(= 1 + \left(\right. - 1 \left.\right) = 0\)

b) \(\frac{17}{8} : \left(\right. \frac{27}{8} + \frac{11}{4} \left.\right)\)

\(= \frac{17}{8} : \left(\right. \frac{27}{8} + \frac{22}{8} \left.\right)\)

\(= \frac{17}{8} : \frac{49}{8} = \frac{17}{8} \cdot \frac{8}{49} = \frac{17}{49}\)

c) \(\frac{1}{5} \cdot \frac{11}{16} + \frac{1}{5} \cdot \frac{5}{16} + \frac{4}{5}\)

\(= \frac{1}{5} \cdot \left(\right. \frac{11}{16} + \frac{5}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. \frac{16}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. 1 + 4 \left.\right) = \frac{1}{5} \cdot 5 = 1\)

d) \(\frac{5}{6} : 25 - 2 + \frac{- 7}{3} \cdot \frac{2}{7}\)

\(= \frac{5}{6} \cdot \frac{1}{25} - 2 + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{6}{3} + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{8}{3} = \frac{1}{30} - \frac{80}{30} = \frac{- 79}{30}\)\(\)

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a) \(\frac{5}{17} - \frac{25}{31} + \frac{12}{17} + \frac{- 6}{31}\)

\(= \left(\right. \frac{5}{17} + \frac{12}{17} \left.\right) + \left(\right. \frac{- 25}{31} + \frac{- 6}{31} \left.\right)\)

\(= \frac{17}{17} + \frac{- 31}{31}\)

\(= 1 + \left(\right. - 1 \left.\right) = 0\)

b) \(\frac{17}{8} : \left(\right. \frac{27}{8} + \frac{11}{4} \left.\right)\)

\(= \frac{17}{8} : \left(\right. \frac{27}{8} + \frac{22}{8} \left.\right)\)

\(= \frac{17}{8} : \frac{49}{8} = \frac{17}{8} \cdot \frac{8}{49} = \frac{17}{49}\)

c) \(\frac{1}{5} \cdot \frac{11}{16} + \frac{1}{5} \cdot \frac{5}{16} + \frac{4}{5}\)

\(= \frac{1}{5} \cdot \left(\right. \frac{11}{16} + \frac{5}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. \frac{16}{16} + 4 \left.\right)\)

\(= \frac{1}{5} \cdot \left(\right. 1 + 4 \left.\right) = \frac{1}{5} \cdot 5 = 1\)

d) \(\frac{5}{6} : 25 - 2 + \frac{- 7}{3} \cdot \frac{2}{7}\)

\(= \frac{5}{6} \cdot \frac{1}{25} - 2 + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{6}{3} + \frac{- 2}{3}\)

\(= \frac{1}{30} - \frac{8}{3} = \frac{1}{30} - \frac{80}{30} = \frac{- 79}{30}\)\(\)

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