Vũ Đức Hải Dương
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2024-03-19 21:00:12
a, Ta có:
\(\dfrac{-3}{8}\);\(\dfrac{5}{-12}\)=\(\dfrac{5.\left(-1\right)}{-12.\left(-1\right)}\)=\(\dfrac{-5}{12}\)
\(\dfrac{-3}{8}\)=\(\dfrac{-3.3}{8.3}\)=\(\dfrac{-9}{24}\);\(\dfrac{-5}{12}\)=\(\dfrac{-5.2}{12.2}\)=\(\dfrac{-10}{24}\)
Vì -9 > -10 nên \(\dfrac{-9}{24}\)>\(\dfrac{-10}{24}\)=> \(\dfrac{-3}{8}\)>\(\dfrac{5}{-12}\)
b, Ta có:
\(\dfrac{3131}{5252}\)=\(\dfrac{3131:101}{5252:101}\)=\(\dfrac{31}{52}\);\(\dfrac{31}{52}\)
Vì 31 = 31 nên \(\dfrac{31}{52}\)=\(\dfrac{31}{52}\)=> \(\dfrac{3131}{5252}\)=\(\dfrac{31}{52}\)
2023-10-30 19:04:21