a)(\(\dfrac{1}{2}\)+1,5).x=\(\dfrac{1}{5}\)

(\(\dfrac{1}{2}\)+\(\dfrac{3}{2}\)).x=\(\dfrac{1}{5}\)

\(\dfrac{2}{1}\).x=\(\dfrac{1}{5}\)

x=\(\dfrac{1}{5}\):\(\dfrac{2}{1}\)

x=\(\dfrac{1}{5}\).\(\dfrac{1}{2}\)

x=\(\dfrac{1}{10}\)

a)\(\dfrac{1}{2}\)-(x+\(\dfrac{1}{3}\))=\(\dfrac{1}{5}\)

x+\(\dfrac{1}{3}\)=\(\dfrac{1}{2}\)-\(\dfrac{1}{5}\)

x+\(\dfrac{1}{3}\)=\(\dfrac{5}{10}\)-\(\dfrac{2}{10}\)

x+\(\dfrac{1}{3}\)=\(\dfrac{3}{10}\)

x=\(\dfrac{3}{10}\)-\(\dfrac{1}{3}\)

x= \(\dfrac{9}{30}\)-\(\dfrac{10}{30}\)

x=\(\dfrac{-1}{30}\)

b)(\(\dfrac{3}{8}\)-\(\dfrac{1}{5}\))+(\(\dfrac{5}{8}\)-x)=\(\dfrac{1}{5}\)

\(\dfrac{3}{8}\)-\(\dfrac{1}{5}\)+(\(\dfrac{5}{8}\)-x)=\(\dfrac{1}{5}\)

\(\dfrac{1}{5}\)+(\(\dfrac{5}{8}\)-x)=\(\dfrac{3}{8}\)-\(\dfrac{1}{5}\)

\(\dfrac{1}{5}\)+(\(\dfrac{5}{8}\)-x)=\(\dfrac{15}{40}\)-\(\dfrac{8}{40}\)

\(\dfrac{1}{5}\)+(\(\dfrac{5}{8}\)-x)=\(\dfrac{7}{40}\)

\(\dfrac{5}{8}\)-x=\(\dfrac{7}{40}\)-\(\dfrac{1}{5}\)

\(\dfrac{5}{8}\)-x=-\(\dfrac{1}{40}\)

x=\(\dfrac{5}{8}\)-(-\(\dfrac{1}{40}\))

x=\(\dfrac{13}{20}\)

a) -1,62+\(\dfrac{2}{5}\)+x=7

\(\dfrac{2}{5}\)+x=7-(-1,62)

\(\dfrac{2}{5}\)+x=8,62

x=8,62-\(\dfrac{2}{5}\)

x=8,22

b)4\(\dfrac{3}{5}\)-x=\(\dfrac{-1}{5}\)+\(\dfrac{1}{2}\)

\(\dfrac{23}{5}\)-x=\(\dfrac{3}{10}\)

x=\(\dfrac{23}{5}\)-\(\dfrac{3}{10}\)

x=\(\dfrac{46}{10}\)-\(\dfrac{3}{10}\)

x=\(\dfrac{43}{10}\)

c)