\(\dfrac{36}{35}=1,0\left(285714\right)\)

\(\dfrac{10}{15}=\dfrac{2}{3}=0,\left(6\right)\)

\(\dfrac{5}{11}=0,\left(45\right)\)

\(\dfrac{2}{13}=0,\left(153846\right)\)

\(\dfrac{15}{82}=0,1\left(82926\right)\)

\(\dfrac{13}{22}=0,5\left(90\right)\)

\(\dfrac{1}{60}=0,01\left(6\right)\)

\(\dfrac{5}{24}=0,208\left(3\right)\)

a) \(\left(\dfrac{1}{6}+\dfrac{5}{9}\right)+\dfrac{4}{9}\)

\(=\dfrac{1}{6}+\dfrac{5}{9}+\dfrac{4}{9}\)

\(=\dfrac{1}{6}+1\)

\(=\dfrac{7}{6}\)

b) \(\dfrac{3}{17}+\left(\dfrac{14}{17}-\dfrac{2}{3}\right)\)

\(=\dfrac{3}{17}+\dfrac{14}{17}-\dfrac{2}{3}\)

\(=1-\dfrac{2}{3}\)

\(=\dfrac{1}{3}\)

c) \(\left(\dfrac{3}{2}-\dfrac{2}{3}\right)+\dfrac{7}{6}\)

\(=\left(\dfrac{9}{6}-\dfrac{4}{6}\right)+\dfrac{7}{6}\)

\(=\dfrac{13}{6}+\dfrac{7}{6}\)

\(=\dfrac{20}{6}\)

Số học sinh giỏi toán là:

\(40\cdot\dfrac{2}{5}=16\left(hs\right)\)

Số học sinh giỏi văn:

\(40\cdot\dfrac{3}{8}=15\left(hs\right)\)

Đáp số: ...

\(\dfrac{3}{5}+x=\dfrac{17}{5}-\left(\dfrac{5}{7}-\dfrac{2}{7}\right)\)

\(\Rightarrow\dfrac{3}{5}+x=\dfrac{17}{5}-\dfrac{3}{7}\)

\(\Rightarrow\dfrac{3}{5}+x=\dfrac{104}{35}\)

\(\Rightarrow x=\dfrac{104}{35}-\dfrac{3}{5}\)

\(\Rightarrow x=\dfrac{83}{35}\)

Ta có: 

\(205< 5\times x< 215\)

\(\Rightarrow5\times x=210\)

\(\Rightarrow x=210:5\)

\(\Rightarrow x=42\)

2) \(B=x-x^2\)

\(B=-x^2+x\)

\(B=-\left(x^2-x+\dfrac{1}{4}\right)+\dfrac{1}{4}\)

\(B=-\left(x-\dfrac{1}{2}\right)^2+\dfrac{1}{4}\)

Mà: \(-\left(x-\dfrac{1}{2}\right)^2\le0\forall x\) nên \(B=-\left(x-\dfrac{1}{2}\right)^2+\dfrac{1}{4}\le\dfrac{1}{4}\)

Dấu "=" xảy ra:
\(-\left(x-\dfrac{1}{2}\right)^2+\dfrac{1}{4}=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{1}{2}\)

Vậy: \(B_{max}=\dfrac{1}{4}\) với \(x=\dfrac{1}{2}\)

1) \(A=4x-x^2+3\)

\(A=-\left(x^2-4x-3\right)\)

\(A=-\left(x^2-4x+4\right)+7\)

\(A=-\left(x-2\right)^2+7\)

Mà: \(-\left(x-2\right)^2\le0\forall x\) nên: \(A=-\left(x-2\right)^2+7\le7\)

Dấu "=" xảy ra:

\(-\left(x-2\right)^2+7=7\)

\(\Rightarrow x=2\)

Vậy: \(A_{max}=7\) khi \(x=2\)

b) \(\left|x+\dfrac{3}{4}\right|-5=-2\)

\(\Rightarrow\left|x+\dfrac{3}{4}\right|=-2+5\)

\(\Rightarrow\left|x+\dfrac{3}{4}\right|=3\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=3\\x+\dfrac{3}{4}=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=-\dfrac{15}{4}\end{matrix}\right.\)

a) \(\left|1-x\right|+0,37=3\)

\(\Rightarrow\left|1-x\right|=2,63\)

\(\Rightarrow\left[{}\begin{matrix}1-x=2,63\\1-x=-2,63\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1,63\\x=3,63\end{matrix}\right.\)

Phân số chỉ 24m vải là:

\(1-\dfrac{1}{5}-\dfrac{1}{3}\cdot\left(1-\dfrac{1}{5}\right)=\dfrac{8}{15}\) 

Độ dài của tấm vải ban đầu:

\(24:\dfrac{8}{15}=45\left(m\right)\)