102 + 2(x - 1) = 2^2 x 50

=> 102 + 2(x - 1) = 4 x 50

=> 102 + 2(x - 1) = 200

=> 2(x - 1) = 200 - 102

=> 2(x - 1) = 198

=> x - 1 = 198:2

=> x - 1 = 99

=> x = 99 + 1

=> x =100

Vậy..

\(\dfrac{3}{4}\times\dfrac{24}{12}+\dfrac{4}{5}:\dfrac{12}{25}-\dfrac{1}{2}\)

\(=\dfrac{3}{4}\times\dfrac{24}{12}+\dfrac{4}{5}\times\dfrac{25}{12}-\dfrac{1}{2}\)

\(=\dfrac{1}{1}\times\dfrac{3}{2}+\dfrac{1}{1}\times\dfrac{5}{3}-\dfrac{1}{2}\)

\(=\dfrac{3}{2}+\dfrac{5}{3}-\dfrac{1}{2}\)

\(=\left(\dfrac{3}{2}-\dfrac{1}{2}\right)+\dfrac{5}{3}\)

\(=1+\dfrac{5}{3}\)

\(=\dfrac{8}{3}\)

\(\dfrac{27^4\times15^3\times8^2}{6^7\times9^3\times15}\)

\(=\dfrac{\left(3^3\right)^4\times15^3\times\left(2^3\right)^2}{\left(2\times3\right)^7\times\left(3^2\right)^3\times15}\)

\(=\dfrac{3^{12}\times15^3\times2^6}{2^7\times3^7\times3^6\times15}\)

\(=\dfrac{3^5\times15^2\times1}{2\times1\times3^6\times1}\)

\(=\dfrac{1\times15^2\times1}{2\times1\times3\times1}\)

\(=\dfrac{225}{6}\)

(P/S: Đây là lần đầu mik làm nên có 1 chút sai sót ạ)

\(4x^2-36=0\)

\(4x^2\)         \(=0+36\)

\(4x^2\)         \(=36\)

  \(x^2\)         \(=36:4\)

  \(x^2\)         \(=9\)

  \(x^2\)         \(=3^2\)

\(=>x=3\)

Vậy...

\(\dfrac{1}{2}-\dfrac{43}{101}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}+\left(-\dfrac{43}{101}\right)\)

\(=0+\left(-\dfrac{43}{101}\right)\)

\(=-\dfrac{43}{101}\)