72 / 96 = ......../ 48= 18/..........= .........../ 12 = 3/..........
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a)\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)
\(\frac{1}{2}xA=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)
\(\frac{1}{4}xA=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\)
\(\frac{1}{4}xA-\frac{1}{2}xA=\frac{1}{3}-\frac{1}{384}\)
\(\frac{1}{4}xA=\frac{127}{384}\)
\(A=\frac{127}{384}:\frac{1}{4}\)
\(A=\frac{127}{96}\)
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)

\(\frac{96}{44}=\frac{48}{22}=\frac{.....}{18}=\frac{4}{.....}=\frac{.....}{3}\)(đề sai)
\(\frac{72}{90}=\frac{60}{75}=\frac{48}{60}=\frac{24}{30}=\frac{4}{5}\)


a) (-48):2+26x(-2)
= (-24) + (-52)
= -76
b) (-96):(-2)+11x(-)?????
SAI ĐỀ
c) (-58)x(-2)+(-5)x(-8)
=116+40
=156
d) 3x(-7)-4x(-3)
=( -21) - (-12)
= (-21)+12
= -9
e) (-8)x(-4)+21x2
=32+42
=74
g) (-16)+32+(-18)x(-2)
= (-16) + 32 + 36
= 16 + 18
= 34
i) (-48)+(-2)x7+(-56):2+4x(-2)
= (-48)+(-14)+(-28)+(-8)
=(-62)+(-28)+(-8)
=(-90)+(-8)
=-98
h) (-16)-18+(-11)x(-2)+(-21)
=(-16)-18+22+(-21)
=(-34)+22-21
=(-34)+1
=-33
k) -18-(-3)x2+32-(-58)
=(-18)+3 x 2 + 32 + 58
=(-18) +6 +32 +58
=(-12)+32+58
= 20+58
=78
m) -2x8-72+31x(-2)
=(-16)-72+(-62)
=(-88)+(-62)
=-150

\(\frac{72}{96}=\frac{36}{48}=\frac{18}{24}=\frac34\)
bạn ơi còn thiếu ............./ 12