tim so abc biet: abc +1133 = abc8
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abc + 1133 = abc8 hay
abc + 1133 = abc x 10 + 8
1133 = abc x 9 + 8
abc x 9 = 1133 – 8 =1125
abc = 1125 : 9
abc = 125
abc+1133=abc8
abc+1133=abcx10+8
abcx10-abc+8=1133
abcx(10-1)=1133-8
abcx9=1125
abc=1125:9
abc=125
tick mình đi!!!!mình chắc chắn đúng luôn!!!!!!!!
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abc + 1133 = abc8
abc + 1133 - 8 = abc x 10 +8
abc + 1133 - 8 = abc x 10
abc + 1125 = abc x 10
abc = 1125 : ( 10 - 1)
abc = 1125 : 9
abc = 125
Vậy abc = 125
Ta có : abc + 1133 = abc x 10 + 8
=> 1133 - 8 = abc x 9
=> 1125 = abc x 9
=> abc = 1125 : 9
=> abc = 125
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abc+1133=abc8
abc+1133=abc x 10+8
1133-8=abc x 10-abc
1125=abc x (10-1)
1125=abc x 9
abc=1125:9
abc=125
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abc + 1133 = abc x 10 + 8
1133 = abc x 9 + 8 ( bớt abc )
1133 - 8 = abc x 9
1125 = abc x 9
abc = 1125 : 9 =
Theo bài ra ta có :
abc + 1133 = abc8
abc + 1133 = 10 x abc + 8
abc + 1133 = 10 x abc + 8
abc + 1133 - 8 = 10 x abc
1133 - 8 = 9 x abc
1125 = 9 x abc
abc = 1125 : 9
abc = 125
Vậy abc = 125
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\(\overline{abc}+1133=\overline{abc8}\)
=> \(\overline{abc}+1133=\overline{abc}.10+8\)
=> \(-9.\overline{abc}+1125=0\)
=> \(-9.\overline{abc}=-1125\)
=> \(\overline{abc}=125\)
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abc + 1133 = abc8
abc + 1133 = abc x 10 + 8
1133 - 8 = abc x 10 - abc
1125 = abc x 9
1125 : 9 = abc
125 = abc
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Ta có :
C là : 8 - 3 = 5
B là : 5 - 3 = 2
A là : 2 - 1 = 1
Vậy ABC = 125
125 + 1133 = 1258
Ta có
\(abc+1133=abc8\)
\(\Rightarrow c+3=8\)\(\Rightarrow c=8-3=5\)
Ta có
\(ab5+1133=ab58\)
\(\Rightarrow b+3=5\)\(\Rightarrow b=5-3=2\)
Ta có
\(a25+1133=a258\)
\(\Rightarrow1+a=2\)\(\Rightarrow a=2-1=1\)
Vậy số abc =125
Tk cho mình vs mình tk lại cho
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abc+1133=abc8
abc+1133=abc*10+8
1125 =abc*9 (cùng bớt abc và 8)
abc =1125:9
abc =125
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làm sao mà tính
1133
+
abc
abc8
=> 3+c=8 => c=5 => 3+b=5 => b=2 => 1+a=2 => a=1
Vậy abc =125