B=998+999x1000/999x1001-1
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CÁC CẬU HỘ MÌNH SỚM NHÉ. AI TRẢ LỜI ĐÚNG VÀ TẮT NHẤT MÌNH SẼ TÍCH CHO NHÉ
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998 + 999 x 1000/999x1001-1
= 998 + {[( 999x1000) /999]x1001)-1
=1001997
998 + 999 x 1000 / 999 x 1001 - 1
= 998 + ([(999 x 1000 ) / 999] x 1001 ) - 1
= 1001997
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Ta có \(A=\frac{1235.2469-1234}{1234.2469+1235}=\frac{\left(1234+1\right).2469-1234}{1234.2469+1235}=\frac{1234.2469+2469-1234}{1234.2469+1235}=\frac{1234.2469+1235}{1234.2469+1235}=1\)
\(B=\frac{4002}{1000.1002-999.1001}=\frac{4002}{\left(1001-1\right)\left(1001+1\right)-\left(1000-1\right)\left(1000+1\right)}=\frac{4002}{\left(1001^2-1\right)-\left(1000^2-1\right)}=\frac{4002}{1001^2-1-1000^2+1}\)
\(B=\frac{4002}{1001^2-1000^2}=\frac{4002}{\left(1001-1000\right)\left(1001+1000\right)}=\frac{4002}{2001}=2\)
Do đó: \(B>A\) ( vì \(2>1\) )
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1/1.2+1/2.3+1/3.4+...+1/999.1000+1
=1-1/2+1/2-1/3+1/3-1/4+...+1/998-1/999+1/999-1/1000+1
=1-1/1000+1
=999/1000+1
=1999/1000
Chuẩn ko cần chỉnh
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{999\times1000}+1\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{999}-\frac{1}{1000}+1\)
\(=1-\frac{1}{1000}+1\)
\(=\frac{999}{1000}+1\)
\(=\frac{1999}{1000}\)
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nếu / là chia thì=1001997
nếu / là phân số thì=998,001
998 + 999 x 1000 / 999 x 1001 -1 = 1001997
úm ba la xì bùa