Tìm x: 96 : x = 8.
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.




a. 96 : 8 : 2 = 6
96 : ( 8 x 2 ) = 6
96 : 8 : 2 = 96 : ( 8 x 2 )
b. 81 : 9 : 3 = 3
81 : ( 9 x 3 ) = 3
81 : 9 : 3 = 81 : ( 9x 3)

\(4\left(3-2x^2\right)-96:\left(-8\right)=112\)
=>\(4\left(3-2x^2\right)+12=112\)
=>\(4\left(3-2x^2\right)=100\)
=>\(3-2x^2=25\)
=>\(2x^2=-22\)
=>\(x^2=-11\)(vô lý)
Vậy: \(x\in\varnothing\)
Để giải phương trình này, ta cần chuyển vế và rút gọn:
⇔⇔⇔⇔4(3−2x2)+896=11212−8x2+12=112−8x2=88x2=−11x=±−11

Cảm ............. ơn
Đã...................liếc
Qua.................liếc
Lại ...................coi
Tui ...................ghi
Cái .......................thứ
Nhảm ...................,rùi
Này ........................Cầu
Cho .........................ai
Thấy .........................cái
Này ..............................sẽ
May ..............................mắn
Cả ?................,,...,...............năm
Ai ..........................................mà
Tick .............................................cho
Tớ .........................................?..............đẹp
Hơn.............................và
Xinh.......................hơn

Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x}{3}=\frac{y}{8}=\frac{z}{5}\Rightarrow\frac{4x}{12}=\frac{3y}{24}=\frac{2z}{10}=\frac{4x+4y-2z}{12+24-10}=\frac{96}{26}=\frac{48}{13}\)
\(\Rightarrow x=\frac{48}{13}\times3=\frac{144}{13}\)
\(y=\frac{48}{13}\times8=\frac{384}{13}\)
\(z=\frac{48}{13}\times5=\frac{240}{13}\)
Vậy ....
Áp dụng t/c DTSBN ta có:
\(\frac{x}{3}=\frac{y}{8}=\frac{z}{5}=\frac{4x+3y-2z}{4.3+3.8-2.5}=\frac{48}{13}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{3}=\frac{48}{13}\Rightarrow x=\frac{144}{13}\\\frac{y}{8}=\frac{48}{13}\Rightarrow y=\frac{384}{13}\\\frac{z}{5}=\frac{48}{13}\Rightarrow z=\frac{240}{13}\end{cases}}\)
Vậy \(x=\frac{144}{13};y=\frac{384}{13};z=\frac{240}{13}\)
hok tốt!

a) x - 96 = (433 - x) - 15
x - 96 = 433 - x - 15
2x = 433 - 15 + 96
2x = 514
x = 257
b) 7x (-x-10) = 0
\(\Leftrightarrow\orbr{\begin{cases}7x=0\\-x-10=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)
c) 17 (3x - 6) (2x - 8) = 0
(3x - 6) (2x - 8) = 0
\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}3x=6\\2x=8\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=4\end{cases}}\)

\(\Rightarrow\left(\frac{x+2}{98}+1\right)+\left(\frac{x+4}{96}+1\right)=\left(\frac{x+6}{94}+1\right)+\left(\frac{x+8}{92}+1\right)\)
\(\Rightarrow\frac{x+100}{98}+\frac{x+100}{96}=\frac{x+100}{94}+\frac{x+100}{92}\)
\(\Rightarrow\frac{x+100}{98}+\frac{x+100}{96}-\frac{x+100}{94}-\frac{x+100}{92}=0\)
\(\Rightarrow\left(x+100\right)\left(\frac{1}{98}+\frac{1}{96}-\frac{1}{94}-\frac{1}{92}\right)=0\)
\(\Rightarrow x+100=0\)
\(\Rightarrow x=0-100=-100\)
96 : x = 8
x = 96 : 8
x = 12.