tìm UC(24;36) theo 2 cách khác nhau.
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a: \(24=2^3\cdot3;40=2^3\cdot5\)
=>\(ƯCLN\left(24;40\right)=2^3=8\)
=>\(ƯC\left(24;40\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
b: \(12=2^2\cdot3;52=2^2\cdot13\)
=>\(ƯCLN\left(12;52\right)=2^2=4\)
=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)
c: \(45=3^2\cdot5;180=2^2\cdot3^2\cdot5\)
=>\(ƯCLN\left(45;180\right)=3^2\cdot5=45\)
=>\(ƯC\left(45;180\right)=\left\{1;-1;3;-3;5;-5;9;-9;15;-15;45;-45\right\}\)
d: \(27=3^3;45=3^2\cdot5;75=3\cdot5^2\)
=>\(ƯCLN\left(27;45;75\right)=3\)
=>\(ƯC\left(27;45;75\right)=\left\{1;-1;3;-3\right\}\)
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B(-15)={0;-15;15;-30;30;...}
ư(-24)={-24;-12;-8;-6;-4;-3;-2;-1;1;2;3;4;6;8;12;24}
ƯC(-12;18)={-6;-4;-3;-2;-1;1;2;3;4;6}
BC-15;20)={0;-60;60;-120;120;...}
B(-15)={...,-45,-30,-15,0,15,30,45,...}
U(-24)={-24,-12,-8,-6,-4,-3,-2,-1,1,2,3,4,6,8,12,24}
UC(-12;18)={-6,-3,-2,-1,1,2,3,6}
BC(-15;20)={-5,-1,1,5}
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12 = 2².3
27 = 3³
ƯCLN(12; 27) = 3
ƯC(12; 27) = Ư(3) = {1; 3}
--------
6 = 2.3
15 = 3.5
ƯCLN(6; 15) = 3
ƯC(6; 15) = Ư(3) = {1; 3}
--------
21 = 3.7
10 = 2.5
12 = 2².3
ƯCLN(21; 10; 12) = 1
ƯC(21; 10; 12) = Ư(1) = {1}
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Bg :
-Tìm ƯCLN + ƯC :
36 = 22 . 32
18 = 2 . 32
24 = 23 . 3
\(\RightarrowƯCLN\left(36,18,24\right)=2.3=6\)
\(\RightarrowƯC\left(36,18,24\right)=Ư\left(6\right)=\left\{1,2,3,6\right\}\)
-Tìm BCNN và BC :
-Phân tích ra thừa số nguyên số như ở trên ((:
\(\Rightarrow BCNN\left(36,18,24\right)=2^3.3^2=72\)
\(\Rightarrow BC\left(36,18,24\right)=B\left(72\right)=\left\{0,72,...\right\}\)
P/s : Hok tốt a~
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a) ƯC của 12;24
Ư(12)={1;2;3;4;6;12}
Ư(24)={1;2;3;4;6;12;24}
ƯC(12;24)={1;2;3;4;6;12}
B và C cậu làm tương tự.
P/s: Tham khảo nha!!
+24=23.3
36=22.32
UCLN(24;36) =22.3=12
+ 36 = 24.1 + 12
24 = 12.2
=> UCLN(24;36) =12