\(tìmx;y;z, biết :\frac{x}{3}=\frac{y}{5}=\frac{z}{7} và 2x+3y-z=-14\)
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\(\dfrac{7}{12}+x=\dfrac{3}{2}\)
\(\Rightarrow x=\dfrac{3}{2}-\dfrac{7}{12}\)
\(\Rightarrow x=\dfrac{18}{12}-\dfrac{7}{12}\)
\(\Rightarrow x=\dfrac{11}{12}\)
Vậy: \(x=\dfrac{11}{12}\)
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2x = 3y = 6
=> 2x = 6 => x = 3
3y = 6 => y = 2
vậy x = 3
y = 2
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3x+|x-2|=14-x
=> 3x+x-2=14-x
=> 4x-2 =14-x
=> 4x+x =14+2
=> 5x = 16
=> x = 16/5
3x+|x-2|=14-x
=> 3x+x-2=14-x
=> 4x-2 =14-x
=> 4x+x =14+2
=> 5x = 16
=> x = 16/5
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0.336xX:0.35=0.6
0,336 * X = 0,6 * 0,35
0,336 * X = 0,21
X = 0,21 : 0,336
X = 0,625
0,336 x X : 0,35 = 0,6
0,336 x X = 0,6 x 0,35
0,336 x X = 0,21
X = 0,21 : 0,336
X = 0,625
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X x 3,6 : 0,9 = 0,17
X x 3,6 = 0,17 x 0,9
X x 3,6 = 0,153
X = 0,153 : 3,6
X = 0,0425
A= 2^2019-2^2018-...-2^2-2^1-1
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ÁP dụng tc dãy tỉ số bằng nhau ta có:
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}=\frac{2x}{6}=\frac{3y}{15}=\frac{z}{7}=\frac{2x+3y-z}{6+15-7}=\frac{-14}{14}=-1\)
\(\Rightarrow x=-3;y=-5;z=-7\)