Question

[Nguyễn Tùng Lâm]

So sánh :\(\frac{n+1}{n+2}\)với \(\frac{n}{n+3}\)\(\left(n>0\right)\)

Answer 1

[I don't need you]

ta có: \(\frac{n+1}{n+2}=\frac{n}{n+2}+\frac{1}{n+2}\) (n>0)

mà \(\frac{n}{n+2}>\frac{n}{n+3}\Rightarrow\frac{n}{n+2}+\frac{1}{n+2}>\frac{n}{n+3}\)

\(\Rightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)

Answer 2

[Phan Thị Xuân Diệu]

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