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Ta có : \(\frac{\left(11,2-10-1,2\right)x\left(3,75-0,75\right)}{2011+3014}=\frac{0x3}{2011+3014}=\frac{0}{2011+3014}=0\)
\(\Rightarrow\left(2000\times7,5+2012:3\right)\times\left(21-3,5\times0,25\right)\times\frac{\left(11,2-10-1,2\right)\times\left(3,75-0,75\right)}{2011+3014}\)
\(=\left(2000\times7,5+2012:3\right)\times\left(21-3,5\times0,25\right)\times0\)
\(=0\)
\(17\cdot\frac{3}{4}-17\cdot0,25+17\cdot\frac{1}{2}\)
\(=17\cdot0,75-17\cdot0,25+17\cdot0,5\)
\(=17\cdot\left(0,75-0,25+0,5\right)\)
\(=17\cdot1\)
\(=17\)
\(17\times\frac{3}{4}-17\times0,25+17\times\frac{1}{2}\)\(=17\times\frac{3}{4}-17\times\frac{1}{4}+17\times\frac{1}{2}\)\(=17\times\left(\frac{3}{4}-\frac{1}{4}+\frac{1}{2}\right)\)
\(=17\times\left(1\right)\)\(=17\)
a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
=> (2,85 - x - 0,5) : 0,25 = 60
=> (2,85 - 0,5) - x = 60 . 0,25
=> 2,35 - x = 15
=> x = 2,35 - 15
=> x = -12,65
Vậy x = -12,65
b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)
\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)
\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)
\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)
\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)
\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)
\(\Rightarrow x=\frac{26}{6}\)
\(\Rightarrow x=\frac{13}{3}\)
Vậy \(x=\frac{13}{3}\)
c) \(35\left(2\frac{1}{5}-x\right)=32\)
\(\Rightarrow2\frac{1}{5}-x=32\div35\)
\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)
\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)
\(\Rightarrow x=\frac{9}{7}\)
Vậy \(x=\frac{9}{7}\)
d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)
\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)
\(\Rightarrow x=\frac{56}{405}\)
Vậy \(x=\frac{56}{405}\)
e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)
\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow4.\frac{12}{11}=11-5\div x\)
\(\Rightarrow11-5\div x=\frac{48}{11}\)
\(\Rightarrow5\div x=11-\frac{48}{11}\)
\(\Rightarrow5\div x=\frac{73}{11}\)
\(\Rightarrow x=5\div\frac{73}{11}\)
\(\Rightarrow x=\frac{55}{73}\)
Vậy \(x=\frac{55}{73}\)
a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
(2,85 - x - 0,5) : 0,25 = 60
(2,85 - x - 0,5) = 60 x 0,25
(2,85 - x - 0,5) = 15
2,35 - x = 15
x = 2,35 - 15
x = -12,65
=17,5 x(1 -3/4 +1/2)
=17,5x(1-0,75+0,5)
=17,5 x 0,75
=13,125
a, 36,4 x 89 + 36,4 x 11
= 36,4 x ( 89 + 11)
= 36,4 x 100
= 3640
b, 7,5 x 16 + 83 x 7,5 + 7,5
= 7,5 x ( 16 + 83) + 7,5
= 7,5 x 99 + 7,5
= 750
Ta có : x . x/5 . 7,5 + x/2 . 9 = 315
=> x . ( x/5 . 7,5 ) + 9x/2 = 315
=> x . ( 7,5x / 5 ) + 4,5 . x = 315
=> x . 1 , 5 . x + 4,5 . x = 315
=> 1 , 5 . x ( x + 3 ) = 315
=> x.( x + 3 ) = 315 : 1,5
=> x . ( x + 3 ) = 210
=> x = 13 ( dư 2 )
a: \(17,5\cdot4\cdot3\cdot25\)
\(=17,5\cdot3\cdot\left(4\cdot25\right)\)
\(=52,5\cdot100=5250\)
b: \(25,6\cdot7,5+25,6\cdot2,5\)
\(=25,6\left(7,5+2,5\right)\)
\(=25,6\cdot10=256\)
c: \(4,52\cdot12,5-2,5\cdot4,25\)
\(=2,5\left(4,52\cdot5-4,25\right)\)
\(=2,5\cdot18,35=45,875\)
d: \(7,7\cdot9+7,7\)
\(=7,7\left(9+1\right)\)
\(=7,7\cdot10=77\)
a: \(7,5+7,5\cdot2+7,5\cdot3+7,5:0,25\)
\(=7,5+7,5\cdot2+7,5\cdot3+7,5\cdot4\)
\(=7,5\cdot\left(1+2+3+4\right)=7,5\cdot10=75\)
b: \(\left(12,35\cdot9+12,35\right)\cdot\left(63-31,5\cdot2\right)\)
\(=12,35\cdot\left(9+1\right)\cdot\left(63-63\right)\)
\(=12,35\cdot10\cdot0=0\)
c: \(0,25\cdot51,5+25\%\cdot24,4+\frac14\cdot24,1\)
\(=0,25\cdot51,5+0,25\cdot24,4+0,25\cdot24,1\)
\(=0,25\cdot\left(51,5+24,4+24,1\right)=0,25\cdot100=25\)