Question

[Trần Hữu Lộc]

Answer 1

[Phước Lộc]

\(g=10\left(\text{m/s}^2\right)=1000\left(\text{cm/s}^2\right)\)

\(\omega=\sqrt{\dfrac{g}{\Delta l}}\Rightarrow\Delta l=2,5\left(cm\right)\)

\(l_c=l_0+\Delta l=30+2,5=32,5\left(cm\right)\)

\(l_{max}=l_c+A=32,5+2=34,5\left(cm\right)\)

\(l_{min}=l_c-A=32,5-2=30,5\left(cm\right)\)

⇒ Chọn phương án A.

Answer 2

[Vũ Đình Tú]

dễ vãi l