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AL
2
1 tháng 12 2015
Ta có
\(\frac{9^{15}.25^{43}}{27^{10}.5^{85}}=\frac{\left(3^2\right)^{15}.\left(5^2\right)^{43}}{\left(3^3\right)^{10}.5^{85}}=\frac{3^{30}.5^{86}}{3^{30}.5^{85}}=5\)
nhớ tick mình nha
1 tháng 12 2015
\(\frac{9^{15}.25^{43}}{27^{10}.5^{85}}=\frac{\left(3^2\right)^{15}.\left(5^2\right)^{43}}{\left(3^3\right)^{10}.5^{85}}=\frac{3^{30}.5^{86}}{3^{30}.5^{85}}=\frac{5\left(3^{30}.5^{85}\right)}{5^{30}.5^{85}}=5\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
6 tháng 7
Bài 1:
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + (\(\frac45\) - \(\frac{3}{17}\) + \(\frac13\)) - \(\frac17\) + (- \(\frac{14}{30}\))
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + \(\frac45\) - \(\frac{3}{17}\) + \(\frac13\) - \(\frac17\) - \(\frac{14}{30}\)
A = (\(\frac15\) + \(\frac45\)) + (\(\frac{3}{17}\) - \(\frac{3}{17}\)) - (\(\frac43-\frac13\)) - \(\frac{30}{210}\) - \(\frac{98}{210}\)
A = 1 + 0 - 1 - (\(\frac{30}{210}+\frac{98}{210}\))
A = 1 - 1 - \(\frac{228}{210}\)
A = 0 - \(\frac{128}{210}\)
A = - \(\frac{64}{105}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
6 tháng 7
Bài 2:
B= (\(\frac58\) - \(\frac{4}{12}\) + \(\frac32\)) - (\(\frac58\) + \(\frac{9}{13}\)) - (\(\frac{-3}{2}\)) + \(\frac{7}{-15}\)
B = \(\frac58\) - \(\frac{4}{12}\) + \(\frac32\) - \(\frac58\) - \(\frac{9}{13}\) + \(\frac32\) - \(\frac{7}{15}\)
B = (\(\frac58\) - \(\frac58\)) + (\(\frac32\) + \(\frac32\)) - (\(\frac13\) + \(\frac{9}{13}\) + \(\frac{7}{15}\))
B = 0 + 3 - (\(\frac{65}{195}\) + \(\frac{135}{195}\) + \(\frac{91}{195}\))
B = 3 - (\(\frac{200}{195}\) + \(\frac{91}{195}\))
B = 3 - \(\frac{97}{65}\)
B = \(\frac{195}{65}\) - \(\frac{97}{65}\)
B = \(\frac{98}{65}\)
5 tháng 10 2016
\(A=\frac{81^4.3^{10}.27^5:3^{12}}{3^{18}:9^3.243^2}=\frac{3^{16}.3^{10}.3^{15}:3^{12}}{3^{18}:3^6.3^{10}}=\frac{3^{29}}{3^{22}}=3^7\)
\(B=\frac{2.55^2-9.55^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=\frac{2.55^2-9.55^2.55^{19}}{25^{10}}:\frac{5\left(21.7^{14}-19.7^{14}\right)}{7.7^{15}+3.7^{15}}=\frac{55^2\left(55^{19}.9-2\right)}{25^{10}}:\frac{5.7^{14}.2}{7^{15}.10}=\frac{55^2\left(55^{19}.9-2\right)}{25^{10}}.\frac{7^{15}.10}{5.7^{14}.2}\)Chịu ==
TN
23 tháng 7 2016
\(G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(=\frac{1}{25}-\frac{4}{27}+\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}+\frac{5}{43}-\frac{4}{7}\)
\(=\left(\frac{1}{25}+\frac{-1}{25}\right)+\left(\frac{-4}{27}+\frac{-23}{27}\right)+\left(\frac{-5}{43}+\frac{5}{43}\right)-\frac{4}{7}\)
\(=0+\left(-1\right)+0-\frac{4}{7}\)
\(=\frac{-11}{7}\)
13 tháng 7 2017
f) \(\frac{25^2.20^4}{5^{10}.4^5}=\frac{\left(5^2\right)^5.\left(4.5\right)^4}{5^{10}.4^5}=\frac{5^{10}.5^4.4^4}{5^{10}.4^5}=\frac{5^{14}.4^4}{5^{10}.4^5}=\frac{5^4}{4}\)
i) \(\frac{9^{15}.81^4}{27^8.3^{20}}=\frac{\left(3^2\right)^{15}.\left(3^4\right)^4}{\left(3^3\right)^8.3^{20}}=\frac{3^{30}.3^{16}}{3^{24}.3^{20}}=\frac{3^{46}}{3^{44}}=3^2=9\)
13 tháng 7 2017
f) Ta có: \(\frac{25^2.20^4}{5^{10}.4^5}\)= \(\frac{\left(5^2\right)^2.\left(4.5\right)^4}{5^{10}.4^5}\)= \(\frac{5^4.4^4.5^4}{5^{10}.4^5}\)= \(\frac{5^8.4^4}{5^{10}.4^5}\)= \(\frac{1}{5^2.4}\)=\(\frac{1}{100}\).
i) Ta có: \(\frac{9^{15}.81^4}{27^8.3^{20}}\)= \(\frac{\left(3^2\right)^{15}.\left(3^4\right)^4}{\left(3^3\right)^8.3^{20}}\)= \(\frac{3^{30}.3^8}{3^{24}.3^{20}}\)= \(\frac{3^{38}}{3^{44}}\)=\(\frac{1}{3^6}\)= \(\frac{1}{729}\)
LH
31 tháng 7 2016
a) \(\frac{2^{11}.9^2}{3^5.16^2}=\frac{2^{11}.3^4}{3^5.2^8}=\frac{2^3}{3}=\frac{8}{3}\)
\(\frac{9^{15}.25^{43}}{27^{10}.5^{85}}=\frac{\left(3^2\right)^{15}.\left(5^2\right)^{43}}{\left(3^3\right)^{10}.5^{85}}=\frac{3^{30}.5^{86}}{3^{30}.5^{85}}=5\)
\(\frac{9^{15}.25^{43}}{27^{10}.5^{85}}=\frac{\left(3^2\right)^{15}.\left(5^2\right)^{43}}{\left(3^3\right)^{10}.5^{85}}=\frac{3^{30}.5^{86}}{3^{30}.5^{85}}=1.5=5.\)
Chúc bạn học tốt!