
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


mk nghĩ là so sánh hai lũy thừa này chứ nhỉ? nếu tính thì số to lắm

Bài 1 :
\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)
\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)
\(\Rightarrow M< N\)
Bài 3 :
a) \(t^2+5t-8\) khi \(t=2\)
\(=5^2+2.5-8\)
\(=25+10-8\)
\(=27\)
b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)
\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)
\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)
c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)
\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)
\(\left(1\right)=1^3=1\)

\(A=1+2^2+2^3+....+2^{60}\)
\(\Rightarrow2A=2+2^3+3^4+...+2^{61}\)
\(\Rightarrow A=2^{61}-2-1\)
Đặt B=2^2+2^3+....+2^60
<=>2B=2^3+2^4+....+2^61
<=>2B-B=(2^3+2^4+....+2^61)-(2^2+2^3+....+2^60)
<=>B=2^61-2^2
<=>B=2^61-4
=>A=1+B
<=>A=1+2^61-4
=>A=2^61-3
vậy A=2^61-3

`#3107.101107`
\(B=1+2+2^2+...+2^{60}\\ 2B=2+2^2+2^3+...+2^{61}\)
\(2B-B=\left(2+2^2+2^3+...+2^{61}\right)-\left(1+2+2^2+...+2^{60}\right)\\ B=2+2^2+2^3+...+2^{61}-1-2-2^2-...-2^{60}\)
\(B=2^{61}-1\)
Vậy, \(B=2^{61}-1.\)