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abc = 6abc : 17
=> abc x 17 = 6000 + abc
=> 17abc = 6000 + abc
=> 17abc - abc = 6000
=> 16abc = 6000
=> abc = 6000 : 16
=> abc = 375
Ta có:abc=6abc:17
Hay abcx17=6abc
abcx17=6000+abc
abcx(17-1)=6000
abcx16=6000
abc=6000:16=375
Đáp số:375
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abc=6abc:17
=>abc x 17=6000+abc
=>abc x 17-abc=6000
=>abc x (17-1)=6000
=>abc x 16=6000
=>abc=375
vậy abc=375
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=> abc x 17 = 6abc
=> 17abc = 6000 + abc
=> 17abc - abc = 6000
=> 16abc = 6000
=> abc = 6000 : 16
=> abc = 375
Vậy abc = 375
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abc = 6abc : 17
=> abc x 17 = 6000 + abc
=> abc x 17 - abc = 6000
=> abc x 16 = 6000
=> abc = 6000 : 16
=> abc = 375
abc=6abc:17
=>abc x 17=6000+abc
=> abc x 17-abc=6000
=>abc x 16=6000
=>abc=375
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Ta có: \(\overline{abc}=\overline{6abc}:17\)
\(\Rightarrow17x\overline{abc}=6000+\overline{abc}\)
\(\Rightarrow16x\overline{abc}=6000\)
\(\overline{abc}=6000:16=375\)
<=> 17 . abc = 6abc
<=> 17abc = 6abc
<=> 17abc = 6000 + abc
<=> 17abc - abc = 6000
<=> 16abc = 6000
<=> abc = 6000 : 16
=> abc = 375
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Ta có :
abc = 6abc : 17
6abc : 17 = abc
( 6000 + abc ) : 16 = abc
6000 : 16 = abc ( bớt 2 vế đi abc )
375 = abc
Mong các banjcho mình xin nha
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1) abc = 6abc : 17
=> abc x 17 = 6abc
=> abc x 17 = 6000 + abc
=> abc x 17 - abc = 6000
=> abc x 16 = 6000
=> abc = 6000 : 16
=> abc = 375
abc=(6000+abc):17
abc=6000:16
abc=375