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\(x^2+2xy+y^2-2x-2y=\left(x+y\right)^2-2\left(x+y\right)=\left(-6\right)^2-2.\left(-6\right)=\)
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\(A=x^2\left(x+y\right)+y^2\left(x+y\right)+2x^2y+2xy^2\)
\(A=x^2\left(x+y\right)+y^2\left(x+y\right)+2xy\left(x+y\right)\)
\(A=\left(x+y\right)\left(x^2+2xy+y^2\right)\)
\(A=\left(x+y\right)\left(x^2+2xy+y^2\right)\)
\(A=\left(x+y\right).\left(x+y\right)^2\)
\(A=\left(x+y\right)^3\)
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\(A=x^2\left(x+y\right)+y^2\left(x+y\right)+2x^2y+2xy^2\)
\(=x^2\left(x+y\right)+y^2\left(x+y\right)+2xy\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2+y^2+2xy\right)\)
\(=\left(x+y\right)\left(x+y\right)^2=\left(x+y\right)^3\)
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B) Ta có: 2x-2y-x2+2xy-y2
⇔ 2(x-y)-(x2-2xy+y2)
⇔ 2(x-y)-(x-y)2
⇔ (x-y)(2-x+y)
Đúng thì tick nhé
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\(A=x^2\left(x+y\right)+y^2\left(x+y\right)+2xy\left(x+y\right)\)
\(\Leftrightarrow A=\left(x+y\right)\left(x^2+2xy+y^2\right)=\left(x+y\right)\left(x+y\right)^2=\left(x+y\right)^3\)
\(A=x^2\left(x+y\right)+y^2\left(x+y\right)+2x^2y+2xy^2\)
\(\Leftrightarrow A=\left(x^2+y^2\right)\left(x+y\right)+2xy\left(x+y\right)\)
\(\Leftrightarrow\left(x^2+2xy+y^2\right)\left(x+y\right)\)
\(\Leftrightarrow A=\left(x+y\right)^2\left(x+y\right)\)
\(\Leftrightarrow A=\left(x+y\right)^3\)
Trả lời:
\(x^2\left(x+y\right)+y^2\left(x+y\right)+2x^2y+2xy^2\)
\(=x^3+x^2y+xy^2+y^3+2x^2y+2xy^2\)
\(=x^3+y^3+3x^2y+3xy^2\)