Question

[Lưu Nguyễn Hà An]

Phép cộng phân số

\(\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{4}{3}+\dfrac{19}{3}=\)

\(\dfrac{3}{4}+\dfrac{4}{4}+\dfrac{5}{4}+\dfrac{6}{4}+\dfrac{x}{2}+\dfrac{8}{2}+\dfrac{9}{4}\)=

HELP

Answer 1

[Lê Minh Quang]

\(\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{4}{3}+\dfrac{19}{3}=\dfrac{1+2+4+19}{3}=\dfrac{26}{3}\)

\(\dfrac{3}{4}+\dfrac{4}{4}+\dfrac{5}{4}+\dfrac{6}{4}+\dfrac{x}{4}+\dfrac{8}{2}+\dfrac{9}{4}\)

=\(\dfrac{3}{4}+\dfrac{4}{4}+\dfrac{5}{4}+\dfrac{6}{4}+\dfrac{x}{4}+\dfrac{16}{4}+\dfrac{9}{4}\)

=\(\dfrac{3+4+5+6+x+16+9}{4}=\dfrac{43+x}{4}\)

Answer 2

[Lưu Nguyễn Hà An]

Cảm ơn và chúc Lê Minh Quang học tốt nhé!

Mình đã tick rùi nha

Thanks