Question

[hhhia]

khai triển nhị thức Newton

_{\(\left(x^2+\dfrac{1}{x}\right)^4\)}

Answer 1

[Nguyễn Lê Phước Thịnh]

(x^2+1/x)^4

\(=C^0_4\cdot\left(x^2\right)^4+C^1_4\cdot\left(x^2\right)^3\cdot\left(\dfrac{1}{x}\right)+C^2_4\cdot\left(x^2\right)^2\cdot\left(\dfrac{1}{x}\right)^2+C^3_4\cdot\left(x^2\right)^1\cdot\left(\dfrac{1}{x}\right)^3+C^4_4\cdot\left(x^2\right)^0\cdot\left(\dfrac{1}{x}\right)^4\)

=x^8+4x^5+6x^3+4/x+1/x^4

Answer 2

[hhhia]

cho hỏi là x ở\(\dfrac{1}{x}\) là nhân như n v