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1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)
CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E
\(\frac27\times5\frac14-\frac27\times3\frac14\)
=\(\frac27\times\left(5\frac14-3\frac14\right)\)
=\(\frac27\times\left(\left(5-3\right)+\left(\frac14-\frac15\right)\right)\)
=\(\frac27\times\left(2+0\right)\)
=\(\frac27\times2\)
=\(\frac47\)
\(\frac37+\frac{5}{13}+\frac{4}{13}\)
=\(\frac37+\left(\frac{5}{13}+\frac{4}{13}\right)\)
=\(\frac37+\frac{9}{13}\)
=\(\frac{39}{91}+\frac{63}{91}\)
=\(\frac{102}{91}\)
\(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\)
=\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{7}{24}\right)\times\frac65+\frac12\)
=\(\frac{5}{24}\times\frac65+\frac12\)
=\(\frac14+\frac12\)
=\(\frac14+\frac24\)
=\(\frac34\)
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}.\frac{5}{19}-\frac{15}{7}\)
\(=\frac{-30}{133}+\frac{65}{-133}-\frac{15}{7}\)
\(=\frac{-30}{133}+\frac{-65}{133}-\frac{15}{7}\)
\(=\frac{-95}{133}-\frac{285}{133}\)
\(=\frac{-380}{133}\)
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}-\frac{5}{19}-\frac{15}{7}\)
\(=-\frac{5}{7}.\frac{6}{19}+\frac{-13}{7}-\frac{5}{19}-\frac{15}{7}\)
\(=\left(\frac{-5}{7}+\frac{-13}{7}-\frac{15}{7}\right).\left(\frac{6}{19}-\frac{5}{19}\right)\)
\(=\frac{-23}{7}.\frac{1}{19}\)
\(=\frac{-23}{133}\)
\(\frac{-5}{7}.\frac{6}{19}+\frac{13}{-7}-\frac{5}{19}-\frac{15}{7}\)
\(=\frac{-5}{6}.\frac{6}{19}+\frac{-13}{7}+\frac{-5}{19}+\frac{-15}{7}\)
\(=\frac{-5}{19}+\frac{-13}{7}+\frac{-5}{19}+\frac{-15}{7}\)
\(=\left(\frac{-5}{19}+\frac{-5}{19}\right)+\left(\frac{-13}{7}+\frac{-15}{7}\right)\)
\(=\frac{-10}{19}+\frac{-26}{7}\)
\(=\frac{-564}{133}\)
\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)
\(=3+6+\left(\frac{14}{19}+\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)
\(=9+1+1+\frac{13}{17}\)
\(=11+\frac{13}{17}\)
\(=\frac{200}{17}\)
??...
-hoi chi do
Mình nghĩ đề phải nhứ thế này
\(\frac{6-\frac{6}{13}+\frac{6}{19}-\frac{6}{27}}{5-\frac{5}{13}+\frac{5}{19}-\frac{5}{27}}\)
= \(\frac{6.\left(1-\frac{1}{13}+\frac{1}{19}-\frac{1}{27}\right)}{5.\left(1-\frac{1}{13}+\frac{1}{19}-\frac{1}{27}\right)}\)
= \(\frac{6}{5}\)
= \(1\frac{1}{5}\)