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\(a,\frac{1}{6}-\frac{2}{3}\)
\(=\frac{1}{6}-\frac{4}{6}=-\frac{3}{6}=-\frac{1}{2}\)

1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)

M= 9/40-11/60+13/84-15/112
M=378/1680-308/1680+260/1680-225/1680
M=\(\frac{378-308+260-225}{1680}\)
M=\(\frac{105}{1680}\)
M= \(\frac{1}{16}\)

\(B=81.\left(\frac{12-\frac{12}{7}-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}\right).\frac{158158158}{711711711}\)
\(\Leftrightarrow B=81.\left(\frac{12\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}:\frac{5\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{6\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\right).\frac{158\left(1001001\right)}{711\left(1001001\right)}\)
\(\Leftrightarrow B=81\left(\frac{12}{3}:\frac{5}{6}\right).\frac{158}{711}\)
\(\Leftrightarrow B=81\left(3.\frac{6}{5}\right).\frac{2}{9}\)
\(\Leftrightarrow B=81.\frac{18}{5}.\frac{2}{9}\)
\(\Leftrightarrow B=\frac{324}{5}\)
Hok tốt!!

A,
26 x 108 - 26 x 12
32-28 + 24 - 20 + 16- 12 + 8 -4
26x (108 - 12 )
4 + 4 + 4 +4
26 x 96
4x4
=156

1.
a/ 70-5.(x-3) = 5.32
=>70-5.(x-3) = 160
=> 5.(x-3) = -90
=> x-3 = -18
=> x = -15
Vậy x = -15.
b/ 2x-3 = 16
=> 2x = 16 + 3
=> 2x = 19
=> x = 9,5
Vậy x = 9,5.
2. Thực hiện phép tính:
a/ 248 + (-12) + 2064 + (-236)
= 236 + 2064 + (-236)
= (236 + (-236)) + 2064
= 0 + 2064
= 2064
b/ /-23/ + (-15) + (-34)
= 23 + (-15) + (-34)
= 8 + (-34)
= -26
c/ 456 + (56 + (-456) + (-38))
= (456 + (-456)) + (56 + (-38))
= 0 + 18
=18
Tiện thể, cho mk hỏi cậu dùng GTTĐ và ngoăc vuông kiểu gì zợ? ^.^

Ta có:
\(A=\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}=\frac{2^{18}.\left(2.3^2\right)^7.3^3+3^{15}.2^{15}}{2^{10}.\left(2.3\right)^{15}+3^{14}.3.5.\left(2^2\right)^{13}}\)
\(=\frac{2^{18}.2^7.3^{14}.3^3+3^{15}.2^{15}}{2^{10}.2^{15}.3^{15}+3^{15}.5.2^{16}}=\frac{2^{25}.3^{17}+2^{15}.3^{15}}{2^{25}.3^{15}+3^{15}.2^{16}.5}=\frac{2^{15}.3^{15}.\left(3^2.2^{10}+1\right)}{2^{16}.3^{15}.\left(2^9+5\right)}\)
\(=\frac{3^2.2^{10}+1}{2^{10}+10}=\frac{9.1024+1}{1024+10}=\frac{9217}{1025}\)
Số số hạng của dãy là: \(\frac{40-12}{1}+1=40-12+1=41-12=29\) (số)
Tổng của dãy số là:
\(\left(40+12\right)\cdot\frac{29}{2}=52\cdot\frac{29}{2}=26\cdot29=754\)
oki