Question

[Vk thánh]

 

Chứng minh các đẳng thức sau:

a)$326+223−432=66" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:20.32px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">$32√6+2√23−4√32=√66$\$\frac{3}{2}\sqrt{6}+2\sqrt{\frac{2}{3}}-4\sqrt{\frac{3}{2}}=\frac{\sqrt{6}}{6}$

b) x6x+2x3+6x):6x=213" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:20.32px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">(x√6x+√2x3+√6x):√6x=213$\left(x\sqrt{\frac{6}{x}}+\sqrt{\frac{2\mathrm{x}}{3}}+\sqrt{6\mathrm{x}}\right):\sqrt{6\mathrm{x}}=2\frac{1}{3}$ với x > 0.