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Question

Biết $\dfrac{x}{2}=\dfrac{y}{3}$

Tính $A=\dfrac{2005x+2006y}{2005x-2006y}$

Nguyễn Phạm Thanh Nga · Accepted Answer

vì $\dfrac{x}{2}=\dfrac{y}{3}\Rightarrow x=\dfrac{2}{3}y$

$\Rightarrow A=\dfrac{2005\cdot\dfrac{2}{3}y+2006y}{2005\cdot\dfrac{2}{3}y-2006y}=-\dfrac{2507}{7}$

Câu trả lời:

vì $\dfrac{x}{2}=\dfrac{y}{3}\Rightarrow x=\dfrac{2}{3}y$

$\Rightarrow A=\dfrac{2005\cdot\dfrac{2}{3}y+2006y}{2005\cdot\dfrac{2}{3}y-2006y}=-\dfrac{2507}{7}$