
\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
b,
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. g) \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\) \(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\) Vây \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\) a) Ta có: \(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\) \(\Leftrightarrow x\cdot\frac{2}{3}=\frac{1}{10}+\frac{1}{2}=\frac{6}{10}\) hay \(x=\frac{6}{10}:\frac{2}{3}=\frac{6}{10}\cdot\frac{3}{2}=\frac{18}{20}=\frac{9}{10}\) Vậy: \(x=\frac{9}{10}\) b) Ta có: \(5\frac{4}{7}:x=13\) \(\Leftrightarrow\frac{39}{7}:x=13\) \(\Leftrightarrow x=\frac{39}{7}:13=\frac{39}{7}\cdot\frac{1}{13}=\frac{3}{7}\) Vậy: \(x=\frac{3}{7}\) c) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\) \(\Leftrightarrow\frac{14}{5}x-50=51\cdot\frac{2}{3}=34\) \(\Leftrightarrow x\cdot\frac{14}{5}=84\) \(\Leftrightarrow x=84:\frac{14}{5}=84\cdot\frac{5}{14}=\frac{420}{14}=30\) Vậy: x=30 d) Ta có: \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\) \(\Leftrightarrow\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}=\frac{-1}{15}\) hay \(x=\frac{1}{3}:\frac{-1}{15}=\frac{1}{3}\cdot\left(-15\right)=\frac{-15}{3}=-5\) Vậy: x=-5 e) Ta có: \(8\frac{2}{3}:x-10=-8\) \(\Leftrightarrow\frac{26}{3}:x=2\) hay \(x=\frac{26}{3}:2=\frac{26}{3}\cdot\frac{1}{2}=\frac{26}{6}=\frac{13}{3}\) Vậy: \(x=\frac{13}{3}\) g) Ta có: \(x+30\%=-1.3\) \(\Leftrightarrow x+\frac{3}{10}=\frac{-13}{10}\) hay \(x=\frac{-13}{10}-\frac{3}{10}=\frac{-16}{10}=\frac{-8}{5}\) Vậy: \(x=\frac{-8}{5}\) i) Ta có: \(3\frac{1}{3}x+16\frac{3}{4}=-13.25\) \(\Leftrightarrow x\cdot\frac{10}{3}+\frac{67}{4}=-\frac{53}{4}\) \(\Leftrightarrow x\cdot\frac{10}{3}=\frac{-53}{4}-\frac{67}{4}=-30\) \(\Leftrightarrow x=-30:\frac{10}{3}=-30\cdot\frac{3}{10}=\frac{-90}{10}=-9\) Vậy: x=-9 k) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\) \(\Leftrightarrow x\cdot\frac{14}{5}-50=51\cdot\frac{2}{3}=34\) \(\Leftrightarrow x\cdot\frac{14}{5}=34+50=84\) hay \(x=84:\frac{14}{5}=84\cdot\frac{5}{14}=30\) Vậy: x=30 m) Ta có: \(\left|2x-1\right|=\left(-4\right)^2\) \(\Leftrightarrow\left|2x-1\right|=16\) \(\Leftrightarrow\left[{}\begin{matrix}2x-1=16\\2x-1=-16\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=17\\2x=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{17}{2}\\x=\frac{-15}{2}\end{matrix}\right.\) Vậy: \(x\in\left\{\frac{17}{2};\frac{-15}{2}\right\}\) \(a;\dfrac{3}{2}x-\dfrac{2}{3}=\dfrac{2}{3}:\dfrac{3}{2}\\
\dfrac{3}{2}x-\dfrac{2}{3}=\dfrac{4}{9}\\
\dfrac{3}{2}x=\dfrac{4}{9}+\dfrac{2}{3}=\dfrac{10}{9}\\
x=\dfrac{10}{9}:\dfrac{3}{2}=\dfrac{20}{27}\\
b;\left(\dfrac{9}{11}-x\right):\left(-\dfrac{10}{11}\right)=1-\dfrac{4}{5}\\
\left(\dfrac{9}{11}-x\right):\left(-\dfrac{10}{11}\right)=\dfrac{1}{5}\\
\dfrac{9}{11}-x=\dfrac{1}{5}\cdot\left(-\dfrac{10}{11}\right)\\
\dfrac{9}{11}-x=-\dfrac{2}{11}\\
x=\dfrac{9}{11}-\left(-\dfrac{2}{11}\right)=\dfrac{9}{11}+\dfrac{2}{11}\\
x=1\\
c;-\dfrac{11}{12}x+\dfrac{3}{4}=-\dfrac{1}{6}\\
-\dfrac{11}{12}x=-\dfrac{1}{6}-\dfrac{3}{4}\\
-\dfrac{11}{12}x=-\dfrac{11}{12}\\
x=\left(-\dfrac{11}{12}\right):\left(-\dfrac{11}{12}\right)=1\) \(d;-\dfrac{5}{4}-\left(1\dfrac{1}{2}+x\right)=4,5\\
\Leftrightarrow-\dfrac{5}{4}-\left(\dfrac{3}{2}+x\right)=4,5\\\dfrac{3}{2}+x=-\dfrac{5}{4}-4,5\\
\dfrac{3}{2}+x=-\dfrac{23}{4}\\
x=-\dfrac{23}{4}-\dfrac{3}{2}\\
x=-\dfrac{29}{4}\\
đ;\left(\dfrac{3}{4}-x:\dfrac{2}{15}\right)\cdot\dfrac{1}{5}=-2,6\\
\dfrac{3}{4}-x:\dfrac{2}{15}=-2,6:\dfrac{1}{5}\\
\dfrac{3}{4}-x:\dfrac{2}{15}=-13\\
x:\dfrac{2}{15}=\dfrac{3}{4}-\left(-13\right)\\
x:\dfrac{2}{15}=\dfrac{55}{4}\\
x=\dfrac{55}{4}\cdot\dfrac{2}{15}=\dfrac{11}{6}\\
e;3-\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{2}{3}\\
\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=3-\dfrac{2}{3}\\
\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{7}{3}\\
\dfrac{1}{6}-x=\dfrac{7}{3}:\dfrac{2}{3}=\dfrac{7}{2}\\
x=\dfrac{1}{6}-\dfrac{7}{2}=-\dfrac{10}{3}\) \(f;\left(1-2x\right)\cdot\dfrac{4}{5}=\left(-2\right)^3\\
\left(1-2x\right)\cdot\dfrac{4}{5}=-8\\
1-2x=-8:\dfrac{4}{5}=-10\\
2x=1-\left(-10\right)=11\\
x=\dfrac{11}{2}\\
g;\dfrac{1}{6}-\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{1}{8}\\
\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{1}{6}-\dfrac{1}{8}=\dfrac{1}{24}\\
\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{1}{24}\Rightarrow x=\dfrac{3}{4}\\\dfrac{1}{2}x-\dfrac{1}{3}=-\dfrac{1}{24}\Rightarrow x=\dfrac{7}{12}\end{matrix}\right.\) \(\frac{3}{2}x-\frac{2}{3}=\frac{2}{3}:\frac{3}{2}\) \(\frac{3}{2}x-\frac{2}{3}=\frac{4}{9}\) \(\frac{3}{2}x=\frac{4}{9}+\frac{2}{3}\) \(\frac{3}{2}x=\frac{10}{9}\) \(x=\frac{10}{9}:\frac{3}{2}\) \(x=\frac{20}{27}\) Vậy x=\(\frac{20}{27}\) \(\left(\frac{9}{11}-x\right):\frac{-10}{11}=1-\frac{4}{5}\) \(\left(\frac{9}{11}-x\right):\frac{-10}{11}=\frac{1}{5}\) \(\frac{9}{11}-x=\frac{1}{5}\cdot\frac{-10}{11}\) \(\frac{9}{11}-x=\frac{-2}{11}\) \(x=\frac{9}{11}-\frac{-2}{11}\) \(x=1\) Vậy x=1 \(\frac{-11}{12}\cdot x+\frac{3}{4}=\frac{-1}{6}\) \(\frac{-11}{12}\cdot x=\frac{-1}{6}-\frac{3}{4}\) \(\frac{-11}{12}\cdot x=\frac{21}{12}\) \(x=\frac{-21}{11}\) Vậy x=\(\frac{-21}{11}\) \(\frac{-5}{4}-\left(1\frac{1}{2}+x\right)=4,5\) \(\frac{3}{2}+x=\frac{-5}{4}-\frac{9}{2}\) \(\frac{3}{2}+x=\frac{23}{4}\) \(x=\frac{17}{4}\) Vậy x=\(\frac{17}{4}\) \(\left(\frac{3}{4}-x:\frac{2}{15}\right)\cdot\frac{1}{5}=-2,6\) \(\frac{3}{4}-x:\frac{2}{15}=\frac{-13}{5}:\frac{1}{5}\) \(\frac{3}{4}-x:\frac{2}{15}=-13\) \(x:\frac{2}{15}=\frac{3}{4}-\left(-13\right)\) \(x:\frac{2}{15}=\frac{45}{4}\) \(x=\frac{3}{2}\) Vậy x=\(\frac{3}{2}\) \(3-\left(\frac{1}{6}-x\right)\cdot\frac{2}{3}=\frac{2}{3}\) \(3-\left(\frac{1}{6}-x\right)=\frac{2}{3}:\frac{2}{3}\) \(3-\left(\frac{1}{6}-x\right)=1\) \(\frac{1}{6}-x=2\) \(x=\frac{1}{6}-2\) \(x=\frac{-11}{6}\) Vậy x=\(\frac{-11}{6}\) \(\left(1-2x\right)\cdot\frac{4}{5}=\left(-2\right)^3\) \(1-2x=\frac{-1}{10}\) \(2x=1-\frac{-1}{10}\) \(2x=\frac{11}{10}\) \(x=\frac{11}{20}\) Vậy x=\(\frac{11}{20}\) \(\frac{1}{6}-\left|\frac{1}{2}\cdot x-\frac{1}{3}\right|=\frac{1}{8}\) \(\left|\frac{1}{2}\cdot x-\frac{1}{3}\right|=\frac{7}{12}\) \(\Rightarrow\frac{1}{2}x-\frac{1}{3}=\frac{7}{12}\) \(\frac{1}{2}x-\frac{1}{3}=\frac{-7}{12}\) \(\frac{1}{2}x=\frac{11}{12}\) \(\frac{1}{2}x=\frac{-1}{4}\) \(x=\frac{11}{6}\) \(x=\frac{-1}{2}\) Vậy \(x\in\left\{\frac{11}{6};\frac{-1}{2}\right\}\) \(\frac{3}{2}x-\frac{2}{3}=\frac{2}{3}:\frac{3}{2}\) \(\frac{3}{2}x=\frac{4}{9}+\frac{6}{9}\) \(\frac{3}{2}x=\frac{10}{9}\) \(x=\frac{10}{9}:\frac{3}{2}\) \(x=\frac{20}{27}\) tk mình đi mình làm nốt cho hjhj ^^ a) (x + 1/2) . (2/3 − 2x) = 0 \(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\) b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\) \(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-2+\frac{3}{7}\) \(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-\frac{11}{7}\) \(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{11}{7}:\frac{11}{5}=-\frac{11}{7}.\frac{5}{11}\) \(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{5}{7}\) \(\Rightarrow x.\frac{44}{7}=-\frac{5}{7}-\frac{3}{7}\) \(\Rightarrow x.\frac{44}{7}=-\frac{8}{7}\) \(\Rightarrow x=-\frac{8}{7}:\frac{44}{7}=-\frac{8}{7}.\frac{7}{44}\) \(\Rightarrow x=-\frac{2}{11}\) c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\) \(\Rightarrow x\left(3\frac{1}{4}-\frac{7}{6}\right)=\frac{5}{12}+\frac{5}{3}\) \(\Rightarrow x\left(\frac{13}{4}-\frac{7}{6}\right)=\frac{25}{12}\) \(\Rightarrow x.\frac{25}{12}=\frac{25}{12}\) \(\Rightarrow x=\frac{25}{12}:\frac{25}{12}\) \(\Rightarrow x=1\) d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\) \(\Rightarrow\left(5\frac{8}{17}-\frac{4}{17}\right):x+\frac{22}{7}:\frac{52}{3}=\frac{4}{11}\) \(\Rightarrow5\frac{4}{17}:x+\frac{33}{182}=\frac{4}{11}\) \(\Rightarrow\frac{89}{17}:x=\frac{4}{11}-\frac{33}{182}\) \(\Rightarrow\frac{89}{17}:x=\frac{365}{2002}\) \(\Rightarrow x=\frac{89}{17}:\frac{365}{2002}\) \(\Rightarrow x\approx28,7\) (số hơi lẻ) e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\) \(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\) \(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\) \(\Rightarrow\left[\begin{array}{nghiempt}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}2x=11\\2x=-\frac{19}{2}\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{11}{2}\\x=-\frac{19}{4}\end{array}\right.\) a)\(\frac{5}{6}-x=-\frac{7}{12}+\frac{2}{3}\) \(\frac{5}{6}-x=\frac{1}{12}\) \(x=\frac{5}{6}-\frac{1}{12}\) \(\Rightarrow x=\frac{3}{4}\) b)\(\left(2,4x-36\right):1\frac{5}{7}=-14\) \(\left(2,4x-36\right)=-24\) \(2,4x=12\) \(\Rightarrow x=5\) c)\(\left(3\frac{1}{2}+2x\right).3\frac{2}{3}=5\frac{1}{3}\) \(3\frac{1}{2}+2x=\frac{16}{11}\) \(2x=-\frac{45}{22}\) \(x=-\frac{45}{44}\) d)\(\frac{5}{6}-\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{3}{8}\) \(\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{11}{24}\) \(\Rightarrow\hept{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{11}{24}\\\frac{1}{2}x-\frac{1}{3}=-\frac{11}{24}\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{19}{12}\\x=-\frac{1}{4}\end{cases}}\) e)\(\left|\frac{1}{4}-2x\right|-\frac{3}{4}=0\) \(\left|\frac{1}{4}-2x\right|=\frac{3}{4}\) \(\Rightarrow\hept{\begin{cases}\frac{1}{4}-2x=\frac{3}{4}\\\frac{1}{4}-2x=-\frac{3}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x=-\frac{1}{4}\\x=\frac{1}{2}\end{cases}}\)