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a,\(\frac{4}{5}\)- \(\frac{7}{6}\)+\(\frac{-6}{15}\)
=\(\frac{24}{30}\)-\(\frac{35}{30}\)+\(\frac{-12}{30}\)
=\(\frac{-11}{30}\)+\(\frac{-12}{30}\)=\(\frac{-23}{30}\)
b, \(\frac{-5}{9}\)x \(\frac{7}{13}\)+\(\frac{6}{13}\)x\(\frac{-5}{9}\)+\(\frac{34}{9}\)
= \(\frac{-5}{9}\)x [ \(\frac{7}{13}\)+\(\frac{6}{13}\)] +\(\frac{34}{9}\)
= \(\frac{-5}{9}\)x1 + \(\frac{34}{9}\)
=\(\frac{-5}{9}\)+\(\frac{34}{9}\)
= \(\frac{29}{9}\)
c, \(\frac{51}{8}\) - [\(\frac{35}{8}\)-\(\frac{1}{2}\)]
= \(\frac{51}{8}\)- \(\frac{31}{8}\)
\(\frac{20}{8}\)
d,\(\frac{7}{3}\)x 1,5 - (\(\frac{11}{10}\) + 50%) : \(\frac{4}{5}\)
= \(\frac{7}{3}\)x\(\frac{3}{2}\)- ( \(\frac{11}{10}\)+ \(\frac{1}{2}\)) : \(\frac{4}{5}\)
= \(\frac{7}{2}\)- \(\frac{8}{5}\): \(\frac{4}{5}\)
= \(\frac{7}{2}\)- \(\frac{2}{1}\)
= \(\frac{7}{2}\) - \(\frac{4}{2}\)
= \(\frac{3}{2}\)
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Cho hình vuông ABCD, M là trung điểm AB. Trên tia đối của tia CB vẽ CN=AM. I là trung điểm MN. Tia DI cắt BC tại E, MN cắt CD tại F. Từ M vẽ MK vuông góc với AB và cắt DE tại K.
a, Cm MKNE là hình thoi (đã làm được)
b, Cm A,I,C thẳng hàng
c, Cho AB=a. Tính diện tích BMEtheo a (Đã làm được)
Giải Giùm mình đi, nhất là câu b
a) \(\left(5^{17}\div5^{16}\right)\times\left(-2\right)^3\)
\(=5\times\left(-8\right)\)
\(=-40\)
b) \(\left(0,5+15\%\right)\times3\frac{1}{13}\)
\(=\left(\frac{50}{100}+\frac{15}{100}\right)\times\frac{40}{13}\)
\(=\frac{65}{100}\times\frac{40}{13}\)
\(=\frac{10}{5}=2\)
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a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
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a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
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`Answer:`
a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)
\(=\frac{1}{6}-\frac{7}{12}\)
\(=-\frac{5}{12}\)
b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)
\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\frac{-17}{5}\)
\(=-\frac{17}{9}\)
c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)
\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)
\(=\frac{77}{325}-1-\frac{2}{13}\)
\(=-\frac{452}{325}\)
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\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)
\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)
\(=\dfrac{3}{11}-\dfrac{2}{3}\)
\(= \dfrac{9}{33}-\dfrac{22}{33}\)
\(= \dfrac{-13}{33}\)
\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)
\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)
\(=\dfrac{35}{27}+\dfrac{-124}{65}\)
\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)
\(=\dfrac{-1073}{1755}\)
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`a)3/5+(-4/9)`
`=3/5-4/9`
`=27/45-20/45`
`=7/45`
`b)3/5+2/5 . 15/8`
`=3/5 + 30/40`
`=3/5+3/4`
`=12/20+15/20`
`=27/20`
`c)7/2 . 8/13 + 8/13 . (-5/2)`
`=8/13 . (7/2 +(-5)/2)`
`=8/13 . 1`
`=8/13`
`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`
`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`
`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`
`= -9/23 ( -5/17 + 22/17)+11+9/23`
`= - 9/23 . 1+11+9/23`
`=-9/23+11+9/23`
`=(-9/23+9/23)+11`
`=0+11`
`=11`
a: =27/45-20/45=7/45
b: =3/5+30/40
=3/5+3/4
=12/20+15/20
=27/20
c: =8/13(7/2-5/2+1)=8/13*2=16/13
d: =9/23*5/17-9/23*22/17+11+9/23
=-9/23+11+9/23
=11
\(\frac{5}{9}.\frac{-4}{17}+\frac{-13}{17}.\frac{5}{9}+2\frac{4}{9}\)
\(=\)\(\frac{5}{9}.\left(\frac{-4}{17}+\frac{-13}{17}\right)+2\frac{4}{9}\)
\(=\frac{5}{9}.\left(-1\right)+\frac{22}{9}\)
\(=\frac{5}{9}+\frac{22}{9}\)
\(=3\)