
\(^{3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. \(3^2\times\frac{1}{243}\times81^2\times\frac{1}{3^3}\) \(=3^2\times\frac{1}{3^5}\times\left(3^4\right)^2\times\frac{1}{3^3}\) \(=\left(3^2\times3^8\right)\times\left(\frac{1}{3^5}\times\frac{1}{3^3}\right)\) \(=3^{10}\times\frac{1}{3^8}\) \(=3^2\) \(=9\) \(\left(4\times2^5\right)\div\left(2^3\times\frac{1}{6}\right)\) \(=\left(2^2\times2^5\right)\div\left(2^3\times\frac{1}{2\times3}\right)\) \(=2^7\div2^2\times3\) \(=2^5\times3\) \(=96\) \(3^2.\frac{1}{243}.81^2.\frac{1}{3^3}\) \(=3^2.\frac{1}{3^5}.\left(3^4\right)^2.\frac{1}{3^3}\) \(=\left(3^2.3^8\right).\left(\frac{1}{3^5}.\frac{1}{3^3}\right)\) \(=3^{10}.3^{-8}\) \(=3^2=9\) \(\left(4.2^5\right):\left(2^3.\frac{1}{6}\right)\) \(=2^7:2^2.3\) \(=2^5.3\) \(=96\) kazuto kirigaya thật là bt làm ko đó ko bt thì nói đi còn bt thì làm đi a) \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}\) \(=1-\frac{1}{32}=\frac{31}{32}\) b) \(\frac{1}{2}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}\)\ \(=\frac{1}{4}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\) \(\frac{1}{4}-\frac{1}{6}=\frac{1}{12}\) Bài 1: a) Ta có: \(\frac{5}{6}-\frac{2}{3}+\frac{1}{4}\) \(=\frac{10}{12}-\frac{8}{12}+\frac{3}{12}\) \(=\frac{2+3}{12}=\frac{5}{12}\) b) Ta có: \(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\) \(=\frac{23}{12}-\frac{5}{12}\cdot\left(\frac{8}{10}-\frac{1}{10}\right)\cdot\frac{-12}{5}\) \(=\frac{23}{12}-\frac{5}{12}\cdot\frac{7}{10}\cdot\frac{-12}{5}\) \(=\frac{23}{12}-\frac{-7}{10}\) \(=\frac{115}{60}+\frac{42}{60}=\frac{157}{60}\) Bài 2: a) Ta có: \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\) \(\Leftrightarrow\frac{1}{2}\cdot x=\frac{1}{5}+\frac{2}{5}=\frac{3}{5}\) \(\Leftrightarrow x=\frac{3}{5}:\frac{1}{2}=\frac{3}{5}\cdot2=\frac{6}{5}\) Vậy: \(x=\frac{6}{5}\) b) Ta có: \(\left(1-2x\right)\cdot\frac{4}{3}=\left(-2\right)^3\) \(\Leftrightarrow\left(1-2x\right)\cdot\frac{4}{3}=-8\) \(\Leftrightarrow1-2x=-8:\frac{4}{3}=-8\cdot\frac{3}{4}=-6\) \(\Leftrightarrow-2x=-6-1=-7\) hay \(x=\frac{7}{2}\) Vậy: \(x=\frac{7}{2}\) a) \(\left(\frac{11}{4}.\frac{-5}{9}-\frac{4}{9}.\frac{11}{4}\right).\frac{8}{33}\) =\(\frac{11}{4}\left(-\frac{5}{9}-\frac{4}{9}\right).\frac{8}{33}\) =\(\frac{11}{4}\cdot-1\cdot\frac{8}{33}\) =\(-\frac{11}{4}\cdot\frac{8}{33}\) =\(-\frac{2}{3}\) b)\(-\frac{1}{4}\cdot\frac{152}{11}+\frac{68}{4}\cdot-\frac{1}{11}\) =\(\frac{-1.152}{4.11}+\frac{68}{4}\cdot\frac{-1}{11}\) =\(\frac{-1.152}{11.4}+\frac{68}{4}\cdot\frac{-1}{11}\) =\(\frac{-1}{11}\cdot\frac{152}{4}+\frac{68}{4}\cdot\frac{-1}{11}\) =\(\frac{-1}{11}\cdot\left(\frac{152}{4}+\frac{68}{4}\right)\) =\(\frac{-1}{11}\cdot55=-5\) c)\(\frac{-2}{3}\cdot\frac{4}{5}+\frac{2}{3}\cdot\frac{3}{5}\) =\(-1\cdot\frac{2}{3}\left(\frac{4}{5}+\frac{3}{5}\right)\) =\(-1\cdot\frac{2}{3}\cdot\frac{7}{5}\) =\(-\frac{2}{3}\cdot\frac{7}{5}\) =\(\frac{-14}{15}\) d) chưa nghĩ ra nhé e) bạn chép sai đề bài rồi mk mới kiểm tra 45 phút nên biết đề bài nè \(\frac{3}{2^2}\cdot\frac{8}{3^2}\cdot\frac{15}{4^2}\cdot...\cdot\frac{899}{30^2}\) =\(\frac{1.3}{2^2}\cdot\frac{2.4}{3^2}\cdot\frac{3.5}{4^2}\cdot...\cdot\frac{29.31}{30^2}\) =\(\frac{1.3.2.4.3.5...29.31}{2.2.3^2.4^2...30.30}\) =\(\frac{1.2.3^2.4^2.5^2....29^2.30.31}{2.2.3^2.4^2.5^2....29^2.30.30}\) =\(\frac{1.31}{2.30}\) =\(\frac{31}{60}\) a)trong ngoac bn dat thau so chung la 11/4 rui tinh binh thuong b)bn tu lam nhe c)dat thua so chung d)tinh trong ngoac ra rui nhan vs e) mk bo tay Câu 8( Mình không viết đè nữa nha) a) 2-1/1.2 + 3-2/2.3 + 4-3/3.4 +…..+ 100-99/99.100 = 1 – 1/2 + 1/2 – 1/3 + 1/3 – 1/4 +…..+ 1/99 – 1/100 = 1 – 1/100 < 1 = 99/100 < 1 Vậy A< 1 A= \(\left(\frac{1}{2}-\frac{7}{13}-\frac{1}{3}\right)+\left(\frac{-6}{13}+\frac{1}{2}+\frac{4}{3}\right)\) A= \(\frac{1}{2}-\frac{7}{13}-\frac{1}{3}-\frac{6}{13}+\frac{1}{2}+\frac{4}{3}\) A= \(\left(\frac{1}{2}+\frac{1}{2}\right)-\left(\frac{7}{13}+\frac{6}{13}\right)-\left(\frac{1}{3}-\frac{4}{3}\right)\) A= \(1-1-\left(-1\right)\) A= \(1\) B= \(0,75+\frac{2}{5}+\left(\frac{1}{9}-\frac{7}{5}+\frac{5}{4}\right)\) B= \(\frac{3}{4}+\frac{2}{5}+\frac{1}{9}-\frac{7}{5}+\frac{5}{4}\) B= \(\left(\frac{3}{4}+\frac{5}{4}\right)+\left(\frac{2}{5}-\frac{7}{5}\right)+\frac{1}{9}\) B= \(2-1+\frac{1}{9}\) B= \(\frac{9}{9}+\frac{1}{9}\) B= \(\frac{10}{9}\) C= \(\left(\frac{-3}{2}.\frac{4}{3}\right).\left(\frac{-9}{2}\right)-\frac{1}{4}\) C = \(-2.\left(\frac{-9}{2}\right)-\frac{1}{4}\) C = \(9-\frac{1}{4}\) C = \(\frac{36}{4}-\frac{1}{4}\) C = \(\frac{35}{4}\) D = \(\frac{5}{4}.\left(\frac{-7}{10}.\frac{5}{4}-\frac{7}{8}.\frac{7}{10}\right)\) D = \(\frac{5}{4}.\left(\frac{-7}{8}-\frac{49}{80}\right)\) D = \(\frac{-35}{32}-\frac{49}{64}\) D = \(\frac{-70}{64}-\frac{49}{64}\) D = \(\frac{-119}{64}\) k mk nha ^_^ a) \(\left(\frac{11}{12}:\frac{44}{16}\right).\left(\frac{-1}{3}+\frac{1}{2}\right)\) \(=\left(\frac{11}{12}.\frac{16}{44}\right).\left(\frac{-2}{6}+\frac{3}{6}\right)\) \(=\frac{1}{3}.\frac{1}{6}\) \(=\frac{1}{18}\) b) \(\frac{\left(-5\right)^2.\left(-5\right)^3.16}{5^4.\left(-2\right)^4}\) \(=\frac{\left(-5\right)^5.2^4}{5^4.\left(-2\right)^4}\) \(=5\) (Có sửa đề lại, nếu có sai thì ib mình sửa lại nhé!) c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\) \(=\frac{15}{2}.\left(\frac{-3}{5}\right)+\frac{5}{2}.\left(\frac{-3}{5}\right)\) \(=\frac{-3}{5}.\left(\frac{15}{2}+\frac{5}{2}\right)\) \(=\frac{-3}{5}.10\) \(=-6\) d) \(\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{5}{4}\) \(=\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right).\frac{4}{5}\) \(=\frac{4}{5}.\left(\frac{-1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{2}\right)\) \(=\frac{4}{5}.\left(\frac{0}{2}+1\right)\) \(=\frac{4}{5}.1=\frac{4}{5}\) a) (1112:4416).(−13+12)(1112:4416).(−13+12) =(1112.1644).(−26+36)=(1112.1644).(−26+36) =13.16=13.16 =118=118 b) (−5)2.(−5)3.1654.(−2)4(−5)2.(−5)3.1654.(−2)4 =(−5)5.2454.(−2)4=(−5)5.2454.(−2)4 =5= c) 7,5:(−53)+212:(−53)7,5:(−53)+212:(−53) =152.(−35)+52.(−35)=152.(−35)+52.(−35) =−35.(152+52)=−35.(152+52) =−35.10=−35.10 =−6=−6 d) (−12+13).45+(23+12):54(−12+13).45+(23+12):54 =(−12+13).45+(23+12).45=(−12+13).45+(23+12).45 =45.(−12+13+23+12)=45.(−12+13+23+12) =45.(02+1)=45.(02+1) =45.1=45