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\(\frac{6}{7}+\frac{2}{5}-\frac{1}{2}+2\frac{38}{91}-\frac{4}{5}=\frac{27300}{31850}+\frac{12740}{31850}-\frac{15925}{31850}+\) \(2\frac{13300}{31850}\)\(-\frac{25480}{31850}\)
\(=2\frac{27300+12740-15925+13300-25480}{31850}\)\(=2\frac{341}{910}\)
HỌC TỐT!!!
a. 6 và 5/3 + 7 và 13/8 +3 và 1/3- 4 và 5/8
=23/3+69/8+4/3-37/8
=391/24+4/3+37/8=141/8-37/8=103/8
b.=(27/5+69/11)-(17/5-52/11)
=642/55+73/55=13
Ta có : \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{5}{11}+\frac{19}{13}+\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\)
\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\right)\)
\(=1+1+2+1=5\)
= (3/5 + 2/5) + (6/11 + 5/11) + (7/13 + 19/13) : 1/2 + 2/3 - 1/6
= (1 + 1 + 2) : (1/2 + 4/6 - 1/6)
= 4 : (1/2 + 1/2)
= 4 : 1
= 4
Vậy kết quả bằng 4
Bài làm :
Ta có :
\(6\frac{5}{3}+7\frac{13}{8}+3\frac{1}{3}-4\frac{5}{8}\)
\(=\left(6\frac{5}{3}+3\frac{1}{3}\right)+\left(7\frac{13}{8}-4\frac{5}{8}\right)\)
\(=\left(\frac{23}{3}+\frac{10}{3}\right)+\left(\frac{69}{8}-\frac{37}{8}\right)\)
\(=\frac{33}{3}+\frac{32}{8}\)
\(=11+4\)
\(=15\)
Tìm \(x\):
a; \(x\) + 35,2 = [25,6 + 3,14] x 3
\(x+\) 35,2 = 28,74 x 3
\(x\) + 35,2 = 86,22
\(x\) = 86,22 - 35,2
\(x\) = 51,02
b; \(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) : \(\frac43\)
\(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) x \(\frac34\)
\(\frac{17}{5}\) : \(x\) = \(\) \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) : \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) x \(\frac{10}{51}\)
\(x\) = \(\frac23\)
c; [\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74\) - \(\frac12\)
[\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74-\frac24\)
[\(x-\frac12\)] x \(\frac53\) = \(\frac54\)
\(x-\frac12\) = \(\frac54\) : \(\frac53\)
\(x-\frac12\) = \(\frac54\) x \(\frac35\)
\(x\) - \(\frac12\) = \(\frac34\)
\(x=\frac34+\frac12\)
\(x=\frac34+\frac24\)
\(x=\) \(\frac54\)
d; [72 - 4 x \(x\)] : 9 = 4
72 - 4 x \(x\) = 4 x 9
72 - 4 x \(x\) = 36
4 x \(x\) = 72 - 36
4 x \(x\) = 36
\(x\) = 36 : 4
\(x\) = 9
Ta có: \(\frac{\frac{6}{7}+\frac{2}{5}-\frac{1}{2}}{\frac{4}{5}+\frac{5}{6}-\frac{1}{3}}+2\frac{38}{91}\)
\(=\frac{\frac{53}{70}}{\frac{13}{10}}+\frac{220}{91}\)
\(=\frac{53}{91}+\frac{220}{91}=3\)