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333444=(3334)111=(1114.81)111333444=(3334)111=(1114.81)111
444333=(4443)111=(1113.64)111444333=(4443)111=(1113.64)111
Dễ thấy 1114.81>1113.641114.81>1113.64
⇒333444>444333⇒333444>444333
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1) 2155 - (174 + 2155) + (-68 + 174)
=2155-174-2155-68+174
=(2155-2155)+(-174+174)-68
=0+0-68
=-68
2) -25 . 72 + 25 . 21 - 49 . 25
=25.(-72+21-49)
=25.(-100)
=-2500
3) 35(14 - 23) - 23(14 - 35)
=35.(-9)-23.(-21)
=(-315)-(-483)
=168
4) 8154 - (674 + 8154) + (-98 + 674)
= 8154-674-8154-98+674
=(8154-8154) + (-674+674) - 98
=0+0-98
=-98
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1. -25.72 + 25.21 - 49.25
= 25.(-72) + 25.21 - 49.25
= 25.(-72 + 21 - 49)
= 25. (-100)
= -2500
2. 35(14 - 23) - 23(14 - 35)
= 35. (-9) - 23. (-9)
= -9(35 - 23)
= -9. 12
= -108
3. 8154 -(674 + 8154) + (-98 + 674)
= 8154 - 674 - 8154 + (-98) + 674
= 8154 - 8154 - 674 + 674 + (-98)
= -98
4. 25.21 + 25.72 + 49.25
= 25(21 + 72 + 49)
= 25. 142
= 3550
5. 27(13 - 16) - 16(13 - 27)
= (27.13 - 27.16) - (16.13 - 16.27)
= 27.13 - 27.16 - 16.13 - 16.27
= 27.13 - 16.13 - 27.16 - 16.27
= 27.13 - 16.13
= 13(27 - 16)
= 13.11
= 143
6. -1911 -(1234 - 1911)
= -1911 - 1234 + 1911
= -1911 + 1911 - 1234
= -1234
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Danh ra dai lam len ban nho chu y dau de nhe, trong day co nhung co 5 phep.
Câu hỏi của Nguyễn Hương Giang - Toán lớp 6 - Học toán với OnlineMath
1) 2155 - (174 + 2155) + (-68+174)
= 2155 - 174 - 2155 + (-68) + 174
=(2155 - 2155) - (174 - 174) + (-68)
= -68
2) -25 . 72 + 25 . 21 - 49 . 25
= 25 . (-72 + 21 - 49)
= 25 . (-100)
= -2500
3) 8154 - (674 + 8154) + (-98 + 674)
= 8154 - 674 - 8154 + (-98) + 674
= (8154 - 8154) - (674 - 674) + (-98)
= -98
4) -25.21+ 25.72 + 49.25
= 25. (-21 + 72 + 49)
= 25. 100
= 2500
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1/ 2155-(174+2155)+(-68+174)
=2155-174-2155-68+174
=[2155+(-2155)]+[(-174)+174]+(-68)
=0+0+(-68)
=-68
2/ -25.72+25.21-49.25
=25.(-72)+25.21-49.25
=25.[(-72)+21+(-49)]
=25.(-100)
=-2500
3/ 35.(14-23)-23.(14-45)
=35.14-35.23-23.14-23.45
=(35.14-23.14)+(-35.23-23.45)
=(35.14-23.14)+(-35.23-45.23)
=14.(35-23)+23.(-35-45)
=14.12+23.(-80)
=168+(-1840)
=-1672
4/ 8154-(674+8154)+(-98+674)
=8154-674-8154-98+674
=[8154+(-8154)]+[(-674)+674]+(-98)
=0+0+(-98)
=-98
5/ -25.21+25.72+49.25
=-12.25+25.72+49.25
=25.(-12+72+49)
=25.109
=2725
Đúng thì chọn đúng cho mình nhé !
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1) 2155 - (174 + 2155) + (-68 + 174)
= 2155 - 174 - 2155 - 68 + 174
= (2155 - 2155) + (-174 + 174) - 68
= 0 + 0 - 68
= -68
2) -25 . 72 + 25 . 21 - 49 . 25
= 25 . (-72) + 25 . 21 - 49 . 25
= 25 . (-72 + 21 - 25)
= 25 . (-76)
= -1900
3) 35 . (14 - 23) - 23 . (14 - 35)
= 35 . 14 - 35 . 23 - 23 . 14 + 23 . 35
= (35 . 14 - 23 . 14) + (-35 . 23 + 23 . 35)
= [14 . (35 - 23)] + 0
= 14 . 12
= 168
4) 8154 - (674 + 8154) + (-98 + 674)
= 8154 - 674 - 8154 - 98 + 674
= (8154 - 8154) + (-674 + 674) - 98
= 0 + 0 - 98
= -98
5) -25 . 21 + 25 . 72 + 49 . 25
= 25 . (-21) + 25 . 72 + 49 . 25
= 25 . (-21 + 72 + 49)
= 25 . 100
= 2500
6) 27 . (13 - 16) - 16 . (13 - 17)
= 27 . 13 - 27 . 16 - 16 . 13 + 16 . 17
= (27 . 13 - 16 . 13) + (-27 . 16 + 16 . 17)
= [13 . (27 - 16)] + [16 . (-27 + 17)]
= (13 . 11) + [16 . (-10)]
= 143 - 160
= -17
1) 2155-2155-(174-174)+-68=0+0+-68=-68
giờ mk ghi kq được ko
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II Giải:
Ta có:
\(\left|x\right|< 2013\Rightarrow x\in\left\{-2012;-2011;...;2011;2012\right\}\)
\(\Rightarrow\) Tổng tất cả các số nguyên \(x\) thỏa mãn \(\left|x\right|< 2013\) là:
\(\left(-2012\right)+\left(-2011\right)+...+2011+2012\)
\(=\) \(\left[\left(-2012\right)+2012\right]+\left[\left(-2011\right)+2011\right]\)
\(=0+0+0+...\)
\(=0\)
Trả lời: Tổng tất cả các số nguyên x thỏa mãn \(\left|x\right|< 2013\) là \(0\)
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1) \( 2155 – (174 + 2155) + (-68 + 174) = -68\) 2) \(-25 . 72 + 25 . 21 – 49 . 25=-2500\) 3) \(35.(14 –23) – 23.(14–35)=168\) 4) \(8154 – (674 + 8154) + (–98 + 674)=-98\) 5) \(25.21+25.72+49.25=2399\) 6) \(27.(13-16)-16.(13-27)=143\) 7) \(–1911 – (1234 – 1911) =-1234\) |
(333 * 445 * (99 985 - 3168)) - (674 + (357 * (3 + 4))) = 14 346 823 972
ks cho mik đi mik ick lại cho !!!
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