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Câu hỏi của ngô thị gia linh - Toán lớp 6 - Học toán với OnlineMath
hay Giải toán trên mạng - Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath
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b) 9/5 : (2 . x + 1) - 2 = 7
9/5 : ( 2 . x + 1) = 7 + 2
9/5 : ( 2 . x + 1) = 9
2 . x + 1 = 9/5 : 9
2 . x + 1 = 1/5
2 . x = 1/5 - 1
2 . x = - 4/5
x = - 4/5 : 2
x = - 2/5
\(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2\frac{1}{2}\right):\frac{7}{4}\)
=\(\frac{59}{10}:\frac{3}{2}-\left(\frac{7}{3}x\frac{9}{2}-\frac{5}{2}\right):\frac{7}{4}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{5}{2}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{15}{6}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-8x\frac{4}{7}\)
=\(\frac{118}{30}-\frac{32}{7}\)
sau bn tự tính nha
\(x+\frac{2}{3}=2\frac{1}{2}\)
\(x+\frac{2}{3}=\frac{5}{2}\)
\(x=\frac{5}{2}-\frac{2}{3}\)
\(x=\frac{11}{6}\)
\(8,75.x+1,25.x=26,3\)
\(x.\left(8,75+1,25\right)=26,3\)
\(x.10=26,3\)
\(x=26,3\div10\)
\(x=2,63\)
a)\(\left(x+3\right)\times5+1=20\Leftrightarrow5x+15=19\)
\(\Leftrightarrow5x=4\Leftrightarrow x=\frac{4}{5}\)
b)sai đề
c)\(2\frac{3}{7}\times x+1\frac{5}{4}=5\frac{3}{42}\)\(\Leftrightarrow\frac{17}{7}\times x+\frac{9}{4}=\frac{71}{14}\) \(\Leftrightarrow\frac{17}{7}\times x+\frac{63}{28}=\frac{142}{28}\)
\(\Leftrightarrow\frac{17}{7}\times x=\frac{79}{28}\Leftrightarrow x=\frac{17}{7}:\frac{79}{28}\) \(\Leftrightarrow x=\frac{17}{7}\times\frac{28}{79}\Leftrightarrow x=\frac{476}{553}=\frac{68}{79}\)
d)\(10\frac{2}{3}-x:\frac{6}{7}=8\frac{1}{3}-6\frac{2}{7}\Leftrightarrow\frac{32}{3}-x:\frac{6}{7}=\frac{25}{3}-\frac{44}{7}\) \(\Leftrightarrow\frac{224}{21}-x:\frac{6}{7}=\frac{75}{21}-\frac{132}{21}\Leftrightarrow-\frac{57}{21}-\frac{224}{21}\)
\(\Leftrightarrow-x:\frac{6}{7}=-\frac{281}{21}\Leftrightarrow-x=-\frac{281}{21}\times\frac{6}{7}\) \(\Leftrightarrow-x=-\frac{1686}{147}\Leftrightarrow x=\frac{562}{49}=11\frac{23}{49}\)
a) ( x + 3 ) × 5 + 1 = 20 ⇔ 5 x + 15 = 19 (x+3)×5+1=20⇔5x+15=19 ⇔ 5 x = 4 ⇔ x = 4 5 ⇔5x=4⇔x= 5 4 b)sai đề c) 2 3 7 × x + 1 5 4 = 5 3 42 2 7 3 ×x+1 4 5 =5 42 3 ⇔ 17 7 × x + 9 4 = 71 14 ⇔ 7 17 ×x+ 4 9 = 14 71 ⇔ 17 7 × x + 63 28 = 142 28 ⇔ 7 17 ×x+ 28 63 = 28 142 ⇔ 17 7 × x = 79 28 ⇔ x = 17 7 : 79 28 ⇔ 7 17 ×x= 28 79 ⇔x= 7 17 : 28 79 ⇔ x = 17 7 × 28 79 ⇔ x = 476 553 = 68 79 ⇔x= 7 17 × 79 28 ⇔x= 553 476 = 79 68 d) 10 2 3 − x : 6 7 = 8 1 3 − 6 2 7 ⇔ 32 3 − x : 6 7 = 25 3 − 44 7 10 3 2 −x: 7 6 =8 3 1 −6 7 2 ⇔ 3 32 −x: 7 6 = 3 25 − 7 44 ⇔ 224 21 − x : 6 7 = 75 21 − 132 21 ⇔ − 57 21 − 224 21 ⇔ 21 224 −x: 7 6 = 21 75 − 21 132 ⇔− 21 57 − 21 224 ⇔ − x : 6 7 = − 281 21 ⇔ − x = − 281 21 × 6 7 ⇔−x: 7 6 =− 21 281 ⇔−x=− 21 281 × 7 6 ⇔ − x = − 1686 147 ⇔ x = 562 49 = 11 23 49 ⇔−x=− 147 1686 ⇔x= 49 562 =11 49 23
\(a.\frac{19}{5}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{19}{5}-\frac{4}{5}\)
\(=\frac{19}{5}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)-\frac{4}{5}\)
\(=\frac{19}{5}\cdot1-\frac{4}{5}\)
\(=\frac{19}{5}-\frac{4}{5}=\frac{15}{5}=3\)
\(b.2\frac{2}{7}\cdot5\frac{2}{5}+\frac{16}{7}\cdot1\frac{3}{5}+\frac{1}{2}\)
\(=\frac{16}{7}\cdot\frac{27}{5}+\frac{16}{7}\cdot\frac{8}{5}+\frac{1}{2}\)
\(=\frac{16}{7}\cdot\left(\frac{27}{5}+\frac{8}{5}\right)+\frac{1}{2}\)
\(=\frac{16}{7}\cdot7+\frac{1}{2}\)
\(=16+\frac{1}{2}=\frac{33}{2}\)
\(c.\frac{3}{7}\cdot3\frac{3}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\frac{15}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\left(\frac{15}{4}-\frac{5}{4}\right)-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\frac{5}{2}-\frac{1}{4}\)
\(=\frac{15}{14}-\frac{1}{4}=\frac{23}{28}\)
Chú ý: \(\cdot:\times\)
(y - 2/5) x 1/2 =1
y - 2/5 =1:1/2
y-2/5 = 1x2/1
y-2/5 =2
y =2+2/5
y =2/1 +2/5
y =10/5+2/5
y = 12/5
4/1