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=>X. 1,7=0,9 . 0,25
=> X . 1,7 = 0,225
=> X =0,225 : 0,17
=> \(\frac{0,225}{0,17}\)
Vậy x= \(\frac{0,225}{0,17}\)
x/0.9=0.25/1.7
x*100/90=25/170
x*17*100/1530=225/1530
=>x*17*100=225
x*1700=225
x=225/1700
x=

\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
\(=>2x+1-\frac{x}{3}=\frac{3}{2}:\left(-0,25\right)\)
\(=>\frac{5x}{3}+1=-6\)
\(=>\frac{5x}{3}=-7\)
\(=>5x=-21\)
\(=>x=-\frac{21}{5}\)
Ủng hộ nha
\(\Rightarrow2x+1-\frac{x}{3}=-6\Rightarrow2x+1-\frac{x}{3}+6=0\Rightarrow\frac{3.\left(2x+1\right)-x+6.3}{3}=0\)
\(\Rightarrow\frac{6x+3-x+18}{3}=0\Rightarrow5x+21=0\Rightarrow x=\frac{-21}{5}\)
Chúc e học tốt Chọn cho anh nha cảm ơn nhìu

Bài làm:
a) \(A=\left|x-0,25\right|\ge0\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|x-0,25\right|=0\Rightarrow x=0,25\)
Vậy GTNN A là 0 khi x = 0,25
b) \(B=\left|x+0,25\right|+1,75\ge1,75\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|x+0,25\right|=0\Rightarrow x=-0,25\)
Vậy GTNN B là 1,75 khi x = -0,25

\(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
\(=\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{2.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{2.\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7.\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)
\(=\frac{2}{7}-\frac{2}{7}\)
\(=0\)
\(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}=\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\)
\(=\frac{2}{7}-\frac{1}{\frac{7}{2}}\)
\(=\frac{2}{7}-\frac{2}{7}=0\)
Study well ! >_<

\(\frac{1}{2}\cdot\left(2-x\right)+0,25=x-\frac{5}{2}:0,4+3\)
\(=>\frac{1}{2}\cdot2-\frac{1}{2}x+\frac{1}{4}=x-\frac{5}{2}:\frac{2}{5}+3\)
\(=>1+\frac{1}{4}+\frac{5}{2}\cdot\frac{5}{2}-3=x-\frac{1}{2}x\)
\(=>\frac{4}{4}+\frac{1}{4}+\frac{25}{4}-\frac{12}{4}=\frac{x}{2}\)
\(=>\frac{18}{4}=\frac{x}{2}\)
\(=>\frac{x}{2}=\frac{9}{2}\)
\(=>x=9\)
Nếu bạn chưa hiểu thì bạn hỏi lại mình nhé! Chúc bạn học tốt!
\(\frac{1}{2}\left(2-x\right)+0,25=x-\frac{5}{2}:0,4+3\)
<=> 1-0,5x+0,25=x-6,25+3
<=> 1,5x=1+0,25+6,25-3=4,5
<=> x=4,5:1,5=3
vậy x=3


\(\dfrac{1}{5}.\left(\dfrac{-7}{3}+\dfrac{2}{8}\right):0,25\)
\(=\dfrac{1}{5}.\left(\dfrac{-56}{24}+\dfrac{6}{24}\right):\dfrac{1}{4}\)
\(=\dfrac{1}{5}.\dfrac{-25}{12}:\dfrac{1}{4}\)
\(=\dfrac{-5}{12}:\dfrac{1}{4}\)
\(=\dfrac{-5}{3}\)

= \(\left(\dfrac{25}{100}+\dfrac{3}{5}-\dfrac{75}{100}+\dfrac{7}{5}\right):\dfrac{-5}{2}\)
= \(\left(\dfrac{25}{100}+\dfrac{3}{5}_{ }+\dfrac{-75}{100}+\dfrac{7}{5}\right).\dfrac{-2}{5}\)
= \(\left(\dfrac{1}{4}+\dfrac{3}{5}+\dfrac{-3}{4}+\dfrac{7}{5}\right).\dfrac{-2}{5}\)
= \(\left[\left(\dfrac{1}{4}+\dfrac{-3}{4}\right)+\left(\dfrac{3}{5}+\dfrac{7}{5}\right)\right].\dfrac{-2}{5}\)
= \(\left(\dfrac{-2}{4}+\dfrac{10}{5}\right).\dfrac{-2}{5}\)
= \(\left(\dfrac{-10}{20}+\dfrac{40}{20}\right).\dfrac{-2}{5}\)
= \(\dfrac{30}{20}.\dfrac{2}{5}\)
= \(\dfrac{30.2}{20.5}\)
= \(\dfrac{6.1}{10.1}\)
= \(\dfrac{6}{10}=\dfrac{3}{5}\)
= (25100+35−75100+75):−52(25100+35−75100+75):−52
= (25100+35+−75100+75).−25(25100+35+−75100+75).−25
= (14+35+−34+75).−25(14+35+−34+75).−25
= [(14+−34)+(35+75)].−25[(14+−34)+(35+75)].−25
= (−24+105).−25(−24+105).−25
= (−1020+4020).−25(−1020+4020).−25
= 3020.253020.25
= 30.220.530.220.5
= 6.110.16.110.1
= 610=35
6070
Cho mình hỏi 2,024 là 2024 hay là 2,024 vậy?