
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


=17+21: [36-(2^2.3+2.11-70^0)]
=17+21:[36-(4.3+22-1)]
=17+21:(36-33)
=17+21:3
=17+7
=24

\(\frac{2^3\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}\)
\(=\frac{2^3\cdot5^2\cdot11\cdot11\cdot7}{2^3\cdot5^2\cdot5\cdot7\cdot7\cdot11}\)
\(=\frac{11}{5\cdot7}=\frac{11}{35}\)
ta có 2^3*5^2*11^2*(7/2)^3*5^3*7^2*11
=(2^3*(7/2)^3*7^2)*(5^2*5^3)*(11^2*11)
=(2^3*7^3/2^3*7^2)*5^5*11^3
=7^5*5^5*11^3

\(\text{7x - x = 5}^{21}:5^{19}+3.2^2-7^0\)
\(\text{(7-1)x=5}^2\text{ + 3. 4 - 1}\)
\(\text{6x = 25 + 12 - 1}\)
\(\text{6x = 36}\)
\(\text{ x = 6}\)
a)7.x-x=521 :519 +3.22 -70
x.(7-1)=52+12-1
x.6 =36
x =36:6=6
b)7.x-2.x=617:615+44:11
x.(7-2)=62+4
x.5 =40
x=40:5=8

a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
b) \(5^3\cdot2-100:4+2^3\cdot5\)
\(=125\cdot2-25+8\cdot5\)
\(=250-25+40\)
\(=225+40=265\)
c) \(6^2:9+50\cdot2+3^3-3\)
\(=36:9+100+27-3\)
\(=4+100+27-3\)
\(=104+27-3=131-3=128\)
d) \(3^2\cdot5+2^3\cdot10-81:3\)
\(=9\cdot5+8\cdot10-27\)
\(=45+80-27\)
\(=125-27=98\)
e) \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^{13-10}-5^2\cdot2^2\)
\(=5^3-\left(5\cdot2\right)^2\)
\(=125-10^2\)
\(=125-100=25\)
f) \(20:2^2+5^9:5^8\)
\(=20:4+5^{9-8}\)
\(=5+5^1=5+5=10\)
g) \(100:5^2+7\cdot3^2\)
\(=10^2:5^2+7\cdot9\)
\(=\left(10:5\right)^2+63\)
\(=2^2+63=4+63=67\)
h) \(84:4+3^9:3^7+5^0\)
\(=21+3^{9-7}+1\)
\(=21+3^2+1\)
\(=21+9+1=30+1=31\)
i) \(29-\left[16+3\cdot\left(51-49\right)\right]\)
\(=29-\left[16+3\cdot2\right]\)
\(=29-\left[16+6\right]\)
\(=29-22=7\)
j) \(\left(15^{19}:5^{17}+3\right)\cdot0:7\)
\(=\left[\left(3\cdot5\right)^{19}:5^{17}+3\right]\cdot0\)
Vì số nào nhân cho 0 cũng bằng 0 nên giá trị biểu thức trên bằng 0
k) \(7^9:7^7-3^2+2^3\cdot5\)
\(=7^{9-7}-9+8\cdot5\)
\(=7^2-9+40\)
\(=49-9+40=40+40=80\)
l) \(1200:2+6^2\cdot2^1+18\)
\(=600+36\cdot2+18\)
\(=600+72+18\)
\(=600+\left(72+18\right)=600+90=690\)
m) \(5^9:5^7+70:14-20\)
\(=5^{9-7}+5-20\)
\(=5^2+5-20\)
\(25+5-20=30-20=10\)
Những câu sau mình làm sau nhé bạn!!!!!!!

a, (x-35)-120=0
x-35=120+0
x-35=120
x=120+35
x=155
b,7x-8=713
7x=713+8
7x=721
x=721:7
x=103
c,4x:17=0
4x=0.17
4x=0
x=0:4
x=0
d,75+(131-x)=205
131-x=205-75
131-x=130
x=131-130
x=1
e,2x-36=4^6:4^3
2x-36=4^6-3
2x-36=4^3
2x-36=48
2x=48-36
2x=12
x=12:2
x=6
f, 2011^2.2011^x=2011^6
2011^x=2011^6: 2011^2
2011^x=2011^6-2
2011^x=2011^4
x=4
bn
\(\text{a/ ( x-35 ) - 120 = 0}\)
\(\Rightarrow\left(x-35\right)=120\)
\(\Rightarrow x=120+35\)
\(x=155\)
\(\text{b/ 7x - 8 = 713}\)
\(\Rightarrow7x=713+8=721\)
\(x=721:7=103\)
\(\text{c/ 4x : 17 = 0}\)
\(4x=0\)
\(x=0\)
\(\text{d/ 75+(131-x) = 205}\)
\(131-x=205-75=130\)
\(x=131-130=1\)
\(e.2x-36=4^6:4^3\)
\(2x-36=4^3=64\)
\(2x=64+36=100\)
\(x=100:2=50\)
\(f.2011^2.2011^x=2011^6\)
\(\text{Ta có công thức }:x^n.x^m=x^{n+m}\)
\(\Rightarrow x=6-2=4\)

Mik chỉ làm 1 câu chung cho bài 1 thôi nha , mấy câu sau giống .
Tìm x , biết :
a) ( x + 1) 2 . ( x - 2 )2 = 0
=> \(\left\{{}\begin{matrix}\left(x+1\right)^2=0\\\left(x-2\right)^2=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
Vậy x = -1 hoặc x = 2 .
Bài 2 , rút gọn biểu thức :
A = a.(b -c) - b.(a+c)
= ab - ac - ( ab + bc )
= ab - ac - ab - bc
= ac - bc
= c .(a-b)
C = (a+3b).c - d - (3a-d).(b+c) - 2c.(b - a) + 2b.(a+d)
= ac + 3bc - d - (3a - d).(b+c) - 2cb - 2ca + 2ba + 2bd
= ac + ( 3bc - 2bc ) - d - ( 3a - d) . ( b+c) +(-2ca + 2ba ) +2db
= ac + bc - d - ( 3a -d) . ( b+c) -2a + cb + 2db
= (a+b).c - d - (3a-d) . ( b+c) - 2a + (2d+c).b
= .........(mik chịu )..........


câu a:
3\(^2\) x 5 + 2\(^3\) x 10 - 81 : 3
= 9 x 5 + 8 x 10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
Câu c:
100 : 5\(^2\) + 7 x 3\(^2\)
= 100 : 25 + 7 x 9
= 4 + 63
= 67
17+21:[36-(22 .3 +2.11-700)]
=17+21:[36-(4 .3 +2.11-1)]
=17+21:[36-(12 +22-1)]
=17+21:[36-(34-1)]
=17+21:(36-33)
=17+21:3
=17+7
=24