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(36 x 452 + 904 x 432 ) : 904
= ( 18 x 2 x 452 + 904 x 432 ) : 904
= ( 18 x 904 + 904 x 432 ) : 904
= (18 + 432) x 904 : 904
= 18 + 432
=450
Ta có : (36 x 452 + 904 x 432) : 904
= (18 x 2 x 452 + 904 x 432) : 904
= (18 x 904 + 904 x 432) : 904
= 904.(18 + 432) : 904
= 18 + 432
= 450

\(\frac13-\left|\frac54-2x\right|=\frac14\)
\(\left|\frac54-2x\right|=\frac13-\frac14\)
\(\left|\frac54-2x\right|=\frac{1}{12}\)
\(\left[\begin{array}{l}\frac54-2x=\frac{1}{12}\\ \frac54-2x=-\frac{1}{12}\end{array}\Rightarrow\left[\begin{array}{l}2x=\frac54-\frac{1}{12}\\ 2x=\frac54-\left(-\frac{1}{12}\right)\end{array}\right.\right.\)
\(\Rightarrow\left[\begin{array}{l}2x=\frac76\\ 2x=\frac43\end{array}\Rightarrow\left[\begin{array}{l}x=\frac76:2=\frac{7}{12}\\ x=\frac43:2=\frac23\end{array}\right.\right.\)
vậy \(x\in\left\lbrace\frac{7}{12};\frac23\right\rbrace\)
\(\frac13-\left\lbrack\frac54-2x\right\rbrack=\frac14\)
\(\frac54-2x=\frac13-\frac14\)
\(\frac54-2x=\frac{4}{12}-\frac{3}{12}\)
\(\frac54-2x=\frac{1}{12}\)
\(2x=\frac54-\frac{1}{12}\)
\(2x=\frac{15}{12}-\frac{1}{12}\)
\(2x=\frac{14}{12}\)
\(2x=\frac76\)
\(x=\frac76:2\)
\(x=\frac76.\frac12\)
\(x=\frac{7}{12}\)
Vậy \(x=\frac{7}{12}\)

1 + 1 = 2
2 + 3= 5
6 + 6 = 12
Tìm x:
X + 3,68 = 4,035
X = 4,035 - 3,68
X = 0,355
5,0165 : X = 5
X = 5,0165 : 5
X = 1,0033
Ủng hộ nha! :)
Bài 1 :
1 + 1 = 2
2 + 3 = 5
6 + 6 = 12
Bài 2 :
x + 3,68 = 4,035
x = 4,035 - 3,68
x = 0,35
5,0165 : x = 5
x = 5,0165 : 5
x = 1.0033

\(\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x...x\left(1-\frac{1}{2014}\right)\)
A = \(\frac{2}{3}x\frac{3}{4}x\frac{4}{5}x...x\frac{2012}{2013}x\frac{2013}{2014}\)
A = \(\frac{2x3x4x...x2012x2013}{3x4x5x...x2013x2014}\)
a = \(\frac{2}{2014}=\frac{1}{1007}\)

Bài 6:
3024 = 6x7x8x9
Vậy 4 số tự nhiên liên tiếp thỏa mãn đề bài là:
6; 7; 8; 9

\(3\frac{3}{4}\times4=\frac{3\times4+3}{4}\times4=\frac{15}{4}\times4=\frac{15\times4}{4}=15\)
\(4\frac{3}{2}\div1\frac{1}{2}=\frac{4\times2+3}{2}\div\frac{1\times2+1}{2}=\frac{11}{2}\div\frac{3}{2}=\frac{11}{2}\times\frac{2}{3}=\frac{11}{3}\)
\(4\frac{3}{4}+2\frac{3}{2}=\frac{4\times4+3}{4}+\frac{2\times2+3}{2}=\frac{19}{4}+\frac{7}{2}=\frac{19}{4}+\frac{14}{4}=\frac{33}{4}\)
\(3\frac{8}{6}-4\frac{1}{3}=\frac{3\times8+6}{6}-\frac{4\times3+1}{3}=\frac{30}{6}-\frac{13}{3}=\frac{30}{6}-\frac{26}{6}=\frac{4}{6}=\frac{2}{3}\)
\(3\frac{2}{4}\)x 4 = \(\frac{14}{4}\)x 4 = \(\frac{56}{4}\)
\(4\frac{3}{2}\): \(1\frac{1}{2}\)= \(\frac{11}{2}\): \(\frac{3}{2}\)= \(\frac{11}{2}\)x \(\frac{2}{3}\)= \(\frac{22}{6}\)= \(\frac{11}{3}\)
\(4\frac{3}{4}\)+ \(2\frac{3}{2}\)= \(\frac{11}{4}\)+ \(\frac{7}{2}\)= \(\frac{25}{4}\)= 6,25
\(3\frac{8}{6}\)- \(4\frac{1}{3}\)= \(\frac{13}{3}\)- \(\frac{13}{3}\)= 0

Đặt \(A=\frac54+\frac58+\frac{5}{16}+\frac{5}{32}+\frac{5}{64}\)
=>\(A\times2=\frac52+\frac54+\frac58+\frac{5}{16}+\frac{5}{32}\)
=>\(2\times A-A=\frac52+\frac54+\frac58+\frac{5}{16}+\frac{5}{32}-\frac54-\frac58-\frac{5}{16}-\frac{5}{32}-\frac{5}{64}\)
=>\(A=\frac52-\frac{5}{64}=\frac{160}{64}-\frac{5}{64}=\frac{155}{64}\)
Ta có: \(1+\frac54+\frac58+\frac{5}{16}+\frac{5}{32}+\frac{5}{64}\)
\(=1+\frac{155}{64}=\frac{64+155}{64}=\frac{219}{64}\)
453
453