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a. 6 và 5/3 + 7 và 13/8 +3 và 1/3- 4 và 5/8
=23/3+69/8+4/3-37/8
=391/24+4/3+37/8=141/8-37/8=103/8
b.=(27/5+69/11)-(17/5-52/11)
=642/55+73/55=13
Bài 1
Câu a, xem lại đề bài
Câu b:
14,58 x 460 + 7,29 x 540 x 2
= 14,58 x 460 + (7,29 x 2) x 540
= 14,58 x 460 + 14,58 x 540
= 14,58 x (460 + 540)
= 14,58 x 1000
= 14580
Câu c: 8,9 : 0,25 + 8,9 : 0,2 + 8,9
= 8,9 x 4 + 8,9 x 5 + 8,9 x 1
= 8,9 x (4 + 5 + 1)
= 8,9 x (9 + 1)
= 8,9 x 10
= 890
\(\frac29\) : \(\frac29\) x \(\frac12\)
= \(\frac29\) x \(\frac92\) x \(\frac12\)
= 1 x \(\frac12\)
= \(\frac12\)
\(\frac27\) : \(\frac23\) - \(\frac17\)
= \(\frac27\times\frac32\) - \(\frac17\)
= \(\frac37\) - \(\frac17\)
= \(\frac27\)
\(\frac23\) x \(\frac34\) x \(\frac45\) : \(\frac15\)
= \(\frac12\) x \(\frac45\) : \(\frac15\)
= \(\frac25\) : \(\frac15\)
= \(\frac25\) x \(\frac51\)
= \(\frac21\)
= 2
a) \(\frac{3}{2}-\frac{5}{6}:x=\frac{5}{15}-\frac{3}{15}\)
\(\Leftrightarrow\frac{3}{2}-\frac{5}{6}:x=\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{3}{2}-\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{41}{30}\)
\(\Leftrightarrow x=\frac{5}{6}:\frac{41}{30}\)
\(\Leftrightarrow x=\frac{25}{41}\)
b) \(x-\frac{6}{7}.\frac{14}{8}=\frac{1}{2}-\frac{2}{5}\)
\(\Leftrightarrow x-\frac{3}{2}=\frac{1}{10}\)
\(\Leftrightarrow x=\frac{1}{10}+\frac{3}{2}\)
\(\Leftrightarrow x=\frac{8}{5}\)
c) \(x:\frac{6}{5}+\frac{2}{3}=\frac{7}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{7}{3}-\frac{2}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}.\frac{6}{5}\)
\(\Leftrightarrow x=2\)
\(\frac{5}{9}\times\frac{12}{7}=\frac{5\times12}{9\times7}=\frac{5\times4\times3}{3\times3\times7}=\frac{20}{21}\)
\(\frac{6}{5}:\frac{8}{3}=\frac{6}{5}\times\frac{8}{3}=\frac{2\times3\times8}{5\times3}=\frac{16}{5}\)
\(\frac{9}{20}\times\frac{5}{12}=\frac{3\times3\times5}{4\times5\times4\times3}=\frac{3}{16}\)
\(\frac{15}{16}:\frac{25}{24}=\frac{15}{16}\times\frac{24}{25}=\frac{3\times5\times4\times2\times3}{4\times2\times2\times5\times5}=\frac{9}{10}\)
\(14\times\frac{5}{21}=\frac{2\times7\times5}{3\times7}=\frac{10}{3}\)
\(10:\frac{5}{3}=10\times\frac{3}{5}=\frac{2\times5\times3}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}\times\frac{1}{10}=\frac{5}{3\times2\times5}=\frac{1}{6}\)
\(\left(5-\frac{23}{7}\right)×\frac{63}{24}+\frac{11}{9}:\frac{2}{3}\)
\(=\frac{12}{7}×\frac{63}{24}+\frac{11}{9}:\frac{2}{3}\)
\(=\frac{9}{2}+\frac{11}{9}:\frac{2}{3}\)
\(=\frac{9}{2}+\frac{11}{6}\)
\(=\frac{19}{3}\)
Tìm \(x\):
a; \(x\) + 35,2 = [25,6 + 3,14] x 3
\(x+\) 35,2 = 28,74 x 3
\(x\) + 35,2 = 86,22
\(x\) = 86,22 - 35,2
\(x\) = 51,02
b; \(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) : \(\frac43\)
\(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) x \(\frac34\)
\(\frac{17}{5}\) : \(x\) = \(\) \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) : \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) x \(\frac{10}{51}\)
\(x\) = \(\frac23\)
c; [\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74\) - \(\frac12\)
[\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74-\frac24\)
[\(x-\frac12\)] x \(\frac53\) = \(\frac54\)
\(x-\frac12\) = \(\frac54\) : \(\frac53\)
\(x-\frac12\) = \(\frac54\) x \(\frac35\)
\(x\) - \(\frac12\) = \(\frac34\)
\(x=\frac34+\frac12\)
\(x=\frac34+\frac24\)
\(x=\) \(\frac54\)
d; [72 - 4 x \(x\)] : 9 = 4
72 - 4 x \(x\) = 4 x 9
72 - 4 x \(x\) = 36
4 x \(x\) = 72 - 36
4 x \(x\) = 36
\(x\) = 36 : 4
\(x\) = 9