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4. (3/4-81)(3^2/5-81)(3^3/6-81)....(3^6/9-81).....(3^2011/2014-81)
mà 3^6/9-81=0 => (3/4-81)(3^2/5-81)....(3^2011/2014-81)=0
\(P=\left(\frac34-81\right)\left(\frac{3^2}{5}-81\right)\cdot\ldots\cdot\left(\frac{3^{15}}{18}-81\right)\)
\(P=\left(\frac34-81\right)\left(\frac{3^2}{5}-81\right)\cdot\ldots\cdot\left(\frac{3^6}{9}-81\right)\cdot\ldots\cdot\left(\frac{3^{15}}{18}-81\right)\)
\(P=\left(\frac34-81\right)\left(\frac{3^2}{4}-81\right)\cdot\ldots\cdot0\cdot\ldots\cdot\left(\frac{3^{15}}{18}-81\right)\)
\(P=0\)
P=(43−81)(532−81)⋅…⋅(18315−81)
\(P = \left(\right. \frac{3}{4} - 81 \left.\right) \left(\right. \frac{3^{2}}{5} - 81 \left.\right) \cdot \ldots \cdot \left(\right. \frac{3^{6}}{9} - 81 \left.\right) \cdot \ldots \cdot \left(\right. \frac{3^{15}}{18} - 81 \left.\right)\)
\(P = \left(\right. \frac{3}{4} - 81 \left.\right) \left(\right. \frac{3^{2}}{4} - 81 \left.\right) \cdot \ldots \cdot 0 \cdot \ldots \cdot \left(\right. \frac{3^{15}}{18} - 81 \left.\right)\)
\(P = 0\)
\(1,\\ a,=\left(\dfrac{1}{4}\right)^3\cdot32=\dfrac{1}{64}\cdot32=\dfrac{1}{2}\\ b,=\left(\dfrac{1}{8}\right)^3\cdot512=\dfrac{1}{512}\cdot512=1\\ c,=\dfrac{2^6\cdot2^{10}}{2^{20}}=\dfrac{1}{2^4}=\dfrac{1}{16}\\ d,=\dfrac{3^{44}\cdot3^{17}}{3^{30}\cdot3^{30}}=3\\ 2,\\ a,A=\left|x-\dfrac{3}{4}\right|\ge0\\ A_{min}=0\Leftrightarrow x=\dfrac{3}{4}\\ b,B=1,5+\left|2-x\right|\ge1,5\\ A_{min}=1,5\Leftrightarrow x=2\\ c,A=\left|2x-\dfrac{1}{3}\right|+107\ge107\\ A_{min}=107\Leftrightarrow2x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{6}\)
\(d,M=5\left|1-4x\right|-1\ge-1\\ M_{min}=-1\Leftrightarrow4x=1\Leftrightarrow x=\dfrac{1}{4}\\ 3,\\ a,C=-\left|x-2\right|\le0\\ C_{max}=0\Leftrightarrow x=2\\ b,D=1-\left|2x-3\right|\le1\\ D_{max}=1\Leftrightarrow x=\dfrac{3}{2}\\ c,D=-\left|x+\dfrac{5}{2}\right|\le0\\ D_{max}=0\Leftrightarrow x=-\dfrac{5}{2}\)
tu hoc moi gioi
nói vậy thì những bài khó tự đi mà làm ngồi đó mà sĩ