Tìm số nguyên \(x\) khác \(0\) thỏa mãn:
\(\frac{40}{x} = \frac{48}{30}\)
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- \(\frac{25}{13}\) + \(\frac{12}{13}\) - \(\frac{9}{17}\) + - \(\frac{25}{17}\)
= -(\(\frac{25}{13}\) - \(\frac{12}{13}\)) - (\(\frac{9}{17}\) + \(\frac{25}{17}\))
= - \(\frac{13}{13}\) - \(\frac{34}{17}\)
= - 1 - 2
= -3
\(-\frac{25}{13}+\frac{12}{13}+\left(-\frac{9}{17}\right)+\left(-\frac{25}{17}\right)\)
= \(\frac{-25+12}{13}+\frac{-9+-25}{17}\)
\(=\frac{-13}{13}+\frac{-34}{17}\)
=\(-1+-2\)
\(=-3\)
I’m going to finish my homework in the morning, then visit my grandparents in the afternoon.
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Ta có: \(\frac{40}{x}=\frac{48}{30}\)
=>\(\frac{40}{x}=\frac{48:6}{30:6}=\frac85=\frac{40}{25}\)
=>x=25