Điền dấu:
1/4 ..... 25/100 61/100 ..... 3/5
3/4 ..... 77/100 13/60 ..... 1/5
12/20 ..... 39/65 82/91 ..... 91/82
Nhanh lên nhé!
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7=4+3*1
10=4+3*2
....................
nho nhan chia truoc cong tru sau
a) 124 + (118 - x) = 217
118 - x = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 219 - 7(x + 1) = 100
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
d) (3x - 6).3 = 3⁴
3x - 6 = 3⁴ : 3
3x - 6 = 3³
3x - 6 = 27
3x = 27 + 6
3x = 33
x = 33 : 3
x = 11
e) 231 - (x - 6) = 1339 : 13
231 - (x - 6) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
a) 124 + (118 - x) = 217
118 - x = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 219 - 7(x + 1) = 100
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
d) (3x - 6) . 3 = 34
(3x - 6) . 3 = 81
(3x - 6) = 81 : 3
(3x - 6) = 27
3x = 27 + 6
3x = 33
x = 33 : 3
x = 11
e) 231 - (x - 6) = 1339 : 13
231 - (x - 6) = 103
(x - 6) = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
a ) 3,71 × 65 + 3,71 × 25 + 10 × 3,71
=\(3,17X\left(65+25+10\right)\)
=\(3,17X100\)
=\(317\)
\(53.39+47.39-53.21-47.21\)
\(=39\left(53+47\right)-21\left(53-47\right)\)
\(=39.100-21.6\)
\(=3900-126\)
\(=3774\)
\(b,5.7.77-7.60+49.25-15.42\)
\(=5.7.77-7.5.12+7.7.5.5-3.5.6.7\)
\(=5.7.77-5.7.12+5.7.5.7-5.7.3.6\)
\(=35.77-35.12+35.35-35.18\)
\(=35.\left(77-12+35-18\right)\)
\(=35.82\)
\(=2870\)
5) 24*(15+49)+12*(50+42)
=24*64+12*92
=24*64+12*2*46
=24*64+24*46
=24*(64+46)
=24*110
=2640
\(\frac{1}{4}=\frac{25}{100}\) \(\frac{61}{100}>\frac{3}{5}\)
\(\frac{3}{4}< \frac{77}{100}\) \(\frac{13}{60}>\frac{1}{5}\)
\(\frac{12}{20}=\frac{39}{65}\) \(\frac{82}{91}< \frac{91}{82}\)
a) \(\frac{1}{4}=\frac{25}{100}\) b) Ta có: \(\frac{3}{5}=\frac{60}{100}< \frac{61}{100}\)nên \(\frac{61}{100}>\frac{3}{5}\)
c) Ta có:\(\frac{3}{4}=\frac{75}{100}< \frac{77}{100}\)nên \(\frac{3}{4}< \frac{77}{100}\) d) Ta có: \(\frac{1}{5}=\frac{12}{60}< \frac{13}{60}\)nên \(\frac{13}{60}>\frac{1}{5}\)
e) Ta có: \(\frac{12}{20}=\frac{3}{5}\)và \(\frac{39}{65}=\frac{3}{5}\)nên \(\frac{12}{20}=\frac{39}{65}\) f) Ta có: \(\frac{82}{91}< 1\)và \(\frac{91}{82}>1\)nên \(\frac{82}{91}< \frac{91}{82}\)