a)(1/2+1/3)+1/6=(../....+.../......)+...../......=..../.....
1/2+(1/3+1/6)=.../.....+(..../.....+...../......)=......
Vậy(1/2+1/3)+1/6......1/2+(1/3+1/6)
Hộ mình nha
Quên đề bài là tính và so sánh giá trị của biểu thức
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=>2/2.3+2/3.4+2/4.5+............+2/x.(x+1)=2007/2019
=>2(1/2.3+1/3.4+1/4.5+.......+1/(x+1))=2007/2019
=>2(1/2-1/3+1/3-1/4+1/4-1/5+.....+1/x-1/x+1)=2007/2019
=>2(1/2-1/2x+1)=2007/2019
=>1-2/x+1=2007/2009=>2/x+1=1-2007/2019=12/2019
=>x+1=336,5.Vay x=335,5
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}\)\(=\frac{2007}{2019}\)
\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x\left(x+1\right)}=\frac{2007}{2019}\)
\(2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x.\left(x+1\right)}\right)\)\(=\frac{2007}{2019}\)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}\)\(=\frac{2007}{2019}\div2\)
\(\frac{1}{2}-\frac{1}{x+1}=\frac{669}{1346}\)
\(\frac{1}{x+1}=\frac{1}{2}-\frac{669}{1346}\)
\(\frac{1}{x+1}=\frac{2}{673}\)
\(\frac{2}{\left(x+1\right)2}=\frac{2}{673}\)
\(\Rightarrow\left(x+1\right)2=673\)
\(\Rightarrow x+1=673\div2\Rightarrow x+1=336,5\Rightarrow x=336,5-1=335,5\)
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mk làm bài 1 thui,bài 2 chỉ qui đồng ms
3a/6 = 3b/4 => 3(a-b)/ (6-4) = 3.4,5/2= 13,5/2 =k
a = 2k=13,5
b = 4k/3 =9
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
MK GHI ĐẦY ĐỦ RA RÙI, BẠN TỰ BẤM MÁY TÍNH LÀM NHA ( MÌNH LƯỜI )
\(A=19\frac{1}{4}+\frac{1}{2}\times2\frac{1}{3}+5,75-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{1}{2}\times\frac{7}{3}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=\frac{77}{4}+\frac{7}{6}+\frac{23}{4}-\frac{1}{6}+74\)
\(A=(\frac{77}{4}+\frac{23}{4})+(\frac{7}{6}-\frac{1}{6})+74\)
\(A=25+1+74\)
\(A=26+74\)
\(A=100\)
\(\frac{\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{2014}}{-\frac{2013}{1}-\frac{2012}{2}-\frac{2011}{3}-...-\frac{1}{2013}}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}}{-\left(2013+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}\right)}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{2014}}{-\left(\frac{2014}{2013}+\frac{2014}{2}+\frac{2014}{3}+....+\frac{2014}{2013}\right)}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+....+\frac{1}{2014}}{-2014\left(\frac{1}{2014}+\frac{1}{2}+\frac{1}{3}+....+\frac{1}{2013}\right)}\)
\(=-\frac{1}{2014}\)