Rút gọn phân số sau: \(\frac{1992\times1990+1}{1994\times1990-3979}\)
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1998*1990+3978=1998*1990+1989*2=1998*(1990+2)=1998*1992
1992*1991-3984=1992*1991-1992*2=1992*(1991-2)=1992*1989
Sau đó rút gọn lại đáp án là 1
\(\text{Ta có : }\dfrac{1989\cdot1990+3978}{1992\cdot1991-3984}=\dfrac{1989\cdot1990+1989\cdot2}{1992\cdot1991-1992\cdot2}\\ =\dfrac{1989\left(1990+2\right)}{1992\left(1991-2\right)}\\ =\dfrac{1989\cdot1992}{1992\cdot1989}\\ =1\)
Đặt:
\(A=\dfrac{1989.1990+3978}{1992.1991-3984}\)
\(A=\dfrac{1989.1990+1989.2}{1992.1991-3984}\)
\(A=\dfrac{1989\left(1990+2\right)}{1992.1991-3984}\)
\(A=\dfrac{1989.1992}{1992.1991-3984}\)
\(A=\dfrac{1989.1992}{1992\left(1989+2\right)-3984}\)
\(A=\dfrac{1989.1992}{1992.1989+1992.2-3984}\)
\(A=\dfrac{1989.1992}{1992.1989+3984-3984}\)
\(A=\dfrac{1989.1992}{1992.1989}=1\)
\(1990\times1990-1992\times1998\)
\(=1990\times1990-\left(1992-2\right)\times\left(1998+2\right)\)
\(=1990\times1990-1990\times1990\)
\(=0\)
mình lam một phần thôi
\(\frac{42134\times846267-423133}{846267\times423133+423134}=\frac{\left(42133+1\right)\times846267-42133}{846267\times423133+423134}\)
\(=\frac{42133\times846267+846267-42133}{846267\times42133+42134}=\frac{846267\times42133+42134}{846267\times42133+42134}=1\)
\(taco:A=\frac{1}{2\cdot32}+\frac{1}{3\cdot33}+\frac{1}{4\cdot34}+...+\frac{1}{1988\cdot2018}\)
\(A=\frac{1}{2}-\frac{1}{32}+\frac{1}{3}-\frac{1}{33}+\frac{1}{4}-\frac{1}{34}+...+\frac{1}{1988}-\frac{1}{2018}\)
\(A=\frac{1}{2}-\frac{1}{2018}\)
\(A=\frac{504}{1009}\)
\(B=\frac{1}{2\cdot1989}+\frac{1}{3\cdot1990}+\frac{1}{4\cdot1991}+...+\frac{1}{31\cdot2018}\)
\(B=\frac{1}{2}-\frac{1}{1989}+\frac{1}{3}-\frac{1}{1990}+\frac{1}{4}-\frac{1}{1991}+...+\frac{1}{31}-\frac{1}{2018}\)
\(B=\frac{1}{2}-\frac{1}{1018}\)
\(B=\frac{504}{1009}\)
tu do \(=>\frac{504}{\frac{1009}{\frac{504}{1009}}}< =>1\)
chuc ban hoc tot nhe >.<