Tìm x biêt: 2+4+6+8+...+x=42
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1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
a, x=1; y=2 => 12
x=2; y=1 => 21
b, x=1; y=5 => 15
x=5; y=1 => 51
c, x=1; y=6 => 16
x=6;y=1 => 61
x=2; y=3=> 23
x=3; y=2 => 32
d, x=1; y=8 => 18
x=2; y=4 => 24
x=4; y=2 => 42
x=8; y=1 => 81
1/ `|x|=10<=> x=\pm 10`
2/ `|x-8|=0<=>x-8=0<=>x=8`
3/ `7+|x|=12<=>|x|=5<=>x=\pm 5`
4/ `|x+1|=3`
$\Leftrightarrow\left[\begin{array}{1}x+1=3\\x+1=-3\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=3\\x=-4\end{array}\right.$
5/ `15-x=16-(14-42)`
`<=>15-x=16+28`
`<=>15-x=44`
`<=>x=-29`
6/ `210-(x-12)=168`
`<=>210-x+12=168`
`<=>222-x=168`
`<=>x=54`
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
a, \(x\) + 99: 3 = 55
\(x\) + 33 = 55
\(x\) = 55 - 33
\(x\) = 22
b, (\(x\) - 25):15 = 20
\(x\) - 25 = 20 x 15
\(x\) - 25 = 300
\(x\) = 300 + 25
\(x\) = 325
c, (3\(x\) - 15).7 = 42
3\(x\) - 15 = 42:7
3\(x\) - 15 = 6
3\(x\) = 6 + 15
3\(x\) = 21
\(x\) = 21: 3
\(x\) = 7
a;80x-64=160
80x=224
x=14/5
b;x-4=42:6
x-4=7
x=11
c;40-x=16*2
40-x=32
x=8
d;20-x=8:4
20-x=2
x=18
`# \text {Ryo}`
`a)`
`80x - 2^2 . 2^4 = 160`
`\Rightarrow 80x - 2^6 = 160`
`\Rightarrow 80x - 64 = 160`
`\Rightarrow 80x = 224`
`\Rightarrow x = 224 \div 80`
`\Rightarrow x = 2,8`
Vậy, `x = 2,8`
`b)`
`(x - 4).6 = 42`
`\Rightarrow x - 4 = 42 \div 6`
`\Rightarrow x - 4 = 7`
`\Rightarrow x = 7 + 4`
`\Rightarrow x = 11`
Vậy, `x = 11`
`c)`
`(40 - x) \div 2 = 16`
`\Rightarrow 40 - x = 16 . 2`
`\Rightarrow 40 - x = 32`
`\Rightarrow x = 40 - 32`
`\Rightarrow x = 8`
Vậy, `x = 8`
`d)`
`(20 - x) . 4 = 8`
`\Rightarrow 20 - x = 8 \div 4`
`\Rightarrow 20 - x = 2`
`\Rightarrow x = 20 - 2`
`\Rightarrow x = 18`
Vậy, `x = 18.`
Số số hạng là :
\(\left(x-2\right):2+1=x:2-1+1=x:2\) (số hạng)
Tổng trên là :
\(\left(x+2\right).x:2:2=42\)
\(\left(x+2\right).x=42.2.2\)
\(\left(x+2\right).x=168\)
\(\left(x+2\right).x=14.12\)
Vậy x = 14