Question

[Nguyễn Thành Nam]

Tính:
\(B=\frac{18^6\cdot2^{12}\cdot4^3\cdot9^3}{16^3\cdot6^9\cdot27^3}\)

Answer 1

[Nguyễn Văn Quyến]

\(B=\frac{18^6\cdot2^{12}\cdot4^3\cdot9^3}{16^3\cdot6^9\cdot27^3}\)

\(=>B=\frac{\left(3^2\cdot2\right)^6\cdot2^{12}\cdot\left(2^2\right)^3\cdot\left(3^2\right)^3}{\left(2^4\right)^3\cdot\left(2\cdot3\right)^9\cdot\left(3^3\right)^3}\)

\(=>B=\frac{3^{12}\cdot2^6\cdot2^{12}\cdot2^6\cdot3^6}{2^{12}\cdot2^9\cdot3^9\cdot3^9}\)

\(=>B=\frac{\left(3^{12}\cdot3^6\right)\cdot\left(2^6\cdot2^{12}\cdot2^6\right)}{\left(2^{12}\cdot2^9\right)\cdot\left(3^9\cdot3^9\right)}\)

\(=>B=\frac{3^{18}\cdot2^{24}}{2^{21}\cdot3^{18}}\)

\(=>B=\frac{2^{24}}{2^{21}}\)

\(=>B=2^{24-21}\)

\(=>B=2^3\)

\(=>B=8\)

Answer 2

[Không Tên]

\(B=\frac{18^6.2^{12}.4^3.9^3}{16^3.6^9.27^3}\)

\(=\frac{2^6.3^{12}.2^{12}.2^6.3^6}{2^{12}.2^9.3^9.3^9}\)

\(=\frac{2^{24}.3^{18}}{2^{21}.3^{18}}\)\(=2^3=8\)