tìm y:
y : 0,1 - y : 4 - y : 0 ,75 = 2,25
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y x 10 - y x \(\frac{1}{4}\)- y x\(\frac{3}{4}\)= 1,25
y x (10 - \(\frac{1}{4}\)- \(\frac{3}{4}\)) = 1,25
y x 9 = 1,25
y = 1,25 : 9
y = \(\frac{5}{36}\)
\(y-36=y\div y+1\)
\(y-36=1+1\)
\(y-36=2\)
\(y=2+36\)
\(y=38\)
Vậy \(y=38\)
\(y-36=y:y+1\)
\(y-36=1+1\)
\(y-36=2\)
\(y=2+36\)
\(y=38\)
2/ Tìm y:
y + \(\dfrac{1}{3}\) x 4 = 12 \(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)
\(y=12-\left(\dfrac{1}{3}\times4\right)=12-\dfrac{4}{3}=\dfrac{32}{3}\)
\(y=\left(\dfrac{12}{35}\times\dfrac{14}{9}\right)-\dfrac{2}{5}=\dfrac{8}{15}-\dfrac{2}{5}=\dfrac{2}{15}\)
\(y.\left(20+16\right)=972\Leftrightarrow36y=972\Leftrightarrow y=27\)
\(\Rightarrow y\times\left(3,2+6,8\right)=26,68\\ \Rightarrow y\times10=26,68\\ \Rightarrow y=26,68:10\\ \Rightarrow y=2,668\)
Ta có : \(y:\frac{1}{10}-y:4-y:\frac{3}{4}=2,25\)
\(\Leftrightarrow y.10-y.\frac{1}{4}-y.\frac{4}{3}=2,25\)
\(\Leftrightarrow y\left(10-\frac{1}{4}-\frac{4}{3}\right)=2,25\)
\(\Leftrightarrow y.\frac{101}{12}=\frac{27}{12}\)
\(y=\frac{27}{12}:\frac{101}{12}=\frac{27}{101}\)
Vậy y=\(\frac{27}{101}\)