5/3 +5/15+5/35....+5/399
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Mk ko chép lại đầu bài đâu,thông cảm nha mk chỉ biết giải ý B
3B=1.2.3+2.3.3+3.4.3+...+1000.1001.3
=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+1000.1001.(1002-999)
=1.2.3-1.2.0+2.3.4-2.3.1+3.4.5-3.4.2+...+1000.1001.1002-1000.1001.999
=(1.2.3+2.3.4+3.4.5+...+1000.1001.1002) - (1.2.0+2.3.1+3.4.2+...+1000.1001.999)
=1000.1001.1002
=>B=(1000.1001.1002):3
=334 334 000
k hộ mk nha!

\(A=\frac{5}{3\cdot5}+\frac{5}{5\cdot7}+\frac{5}{7\cdot9}+......+\frac{5}{19\cdot21}\)
\(A=\frac{5}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+......+\frac{1}{19}-\frac{1}{21}\right)\)
\(A=\frac{5}{2}\left(\frac{1}{3}-\frac{1}{21}\right)\)
còn lại tự tính nha
ok xong r đó
\(A=\frac{5}{15}+\frac{5}{35}+\frac{5}{63}+...+\frac{5}{399}\)
\(A=\frac{5}{3.5}+\frac{5}{5.7}+\frac{5}{7.9}+...+\frac{5}{19.21}\)
\(2A=5\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{19.21}\right)\)
\(2A=5\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\right)\)
\(2A=5\left(\frac{1}{3}-\frac{1}{21}\right)\)
\(2A=5.\frac{2}{7}\)
\(2A=\frac{10}{7}\)
\(\Rightarrow A=\frac{5}{7}\)

Ta có:
\(A=\frac{5}{15}+...+\frac{5}{399}\)
\(\Rightarrow A=5.\left(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{19.21}\right)\)
\(\Rightarrow A=\frac{5}{2}.\left(\frac{1}{3}-\frac{1}{5}+...+\frac{1}{19}-\frac{1}{21}\right)\)
\(\Rightarrow A=\frac{5}{2}.\left(\frac{1}{3}-\frac{1}{21}\right)\)
\(\Rightarrow A=\frac{5}{7}\)

a. 215 - 5 + 10 = 210 + 10 = 220
b. 13 + (-17) = -4
c. 25 . 5 . 2014 . 4 . 2 = (25 . 4) . (5 . 2) . 2014 = 100 . 10 . 2014 = 1000 . 2014 = 2014000
đ. 24.35 + 76.35 - 500 = (24 + 76) . 35 - 500 = 100 . 35 - 500 = 3500 - 500 = 3000
e. 3 + 7 + 11 + 15 + ... + 399 + 403 = 406 . 101 : 2 = 20503

Bài làm:
\(A=\frac{4^2}{15}.\frac{5^2}{24}.\frac{6^2}{35}.....\frac{20^2}{399}=\frac{4^2}{3.5}.\frac{5^2}{4.6}.\frac{6^2}{5.7}.....\frac{20^2}{19.21}=\frac{\left(4.5.6.....20\right)\left(4.5.6.....20\right)}{\left(3.4.5.....19\right)\left(5.6.7.....21\right)}=\frac{20.4}{3.21}=\frac{80}{63}\)
Học tốt!!!!

\(=\frac{4.4}{3.5}.\frac{5.5}{4.6}......\frac{20.20}{19.21}\)
\(=\left(\frac{4.5...20}{3.4....19}\right).\left(\frac{4.5...20}{5.6....21}\right)\)
\(=\frac{20}{3}.\frac{4}{21}\)
\(=\frac{80}{63}\)

1 + 3 - 5 - 7 + 9+11-13-15+...-397-399
có (399-1):2+1=200 chữ số
=(1 + 3 - 5 - 7) + (9 + 11 - 13 - 15)+ ... + (393 + 395 - 397 - 399)
=(-8) + (-8) + ... + (-8)
có 200 : 4 = 50 số -8
=(-8) x 50
=-400

=(1+3-5-7)+(9+11-13-15)+........+(393+395-397-399) =-8+(-8)+.....+(-8) có 50 so -8 =-8 .50=-400

Ta có : 1+3-5-7+9+11-13-15+..............+395-397-399
= (1+3-5-7)+(9+11-13-15)+.........+(393+395-397-399) ( 50 nhóm)
= (-8)+(-8)+................+(-8) ( 50 số)
= (-8). 50
= -400

SSH: (399-1):2+1= 200
Neu chia moi nhom 4 so thi so cap so la:
200:4 = 50
Ta co:
B=1+3-5-7+9+11-13-15+...+393+395-397-399
B= (1+3-5-7)+(9+11-13-15)+...+(393+395-397-399)
B= -8 + -8 +...+ -8
B= -8 . 50
B= -400
SSH: (399-1):2+1= 200
Neu chia moi nhom 4 so thi so cap so la:
200:4 = 50
Ta co:
A=1+3-5-7+9+11-13-15+...+393+395-397-399
A= (1+3-5-7)+(9+11-13-15)+...+(393+395-397-399)
A= -8 + -8 +...+ -8
A= -8 . 50
A= -400
\(\frac53+\frac{5}{15}+\frac{5}{35}+\ldots+\frac{5}{399}\)
\(=\frac{5}{1\cdot3}+\frac{5}{3\cdot5}+\frac{5}{5\cdot7}+\cdots+\frac{5}{19\cdot21}\)
\(=\frac52\cdot\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}_{}+\cdots+\frac{2}{19\cdot21}\right)\)
\(=\frac52\cdot\left(\frac11-\frac13+\frac13-\frac15+\cdots+\frac{1}{19}-\frac{1}{21}\right)\)
\(=\frac52\cdot\left(1-\frac{1}{21}\right)=\frac52\cdot\frac{20}{21}=\frac{50}{21}\)
\(\frac53+\frac{5}{15}+\frac{5}{35}+\cdots+\frac{5}{399}\)
\(=\frac52\cdot\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\cdots+\frac{2}{19\cdot21}\right)\)
\(=\frac52\cdot\left(\frac11-\frac13+\frac13-\frac15+\cdots+\frac{1}{19}-\frac{1}{21}\right)\)
\(=\frac52\cdot\left(\frac11-\frac{1}{21}\right)=\frac52\cdot\frac{20}{21}=\frac{50}{21}\)